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3 years ago

The process of the classifying living thing is

Chemistry

1 answer:

jok3333 [9.3K]3 years ago

7 0

Answer:

D. all of these

Explanation:

In the classification of organisms, they are placed into groups which they appropriately fit into.

All the choices given correctly shows the process of classifying organisms. This aspect of biology is described as taxonomy.

Based on characteristics of organisms, they are put into the same groups
Also, we can identify the related family and genus in which a discovered organism can be put into.
They phylogenetic relationship between organisms are important for classification.

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An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at

Yakvenalex [24]

Answer:

68.3g

Explanation:

1. Word equation:

mercury(II) oxide → mercury + oxygen

2. Balanced molecular equation:

2HgO → 2Hg + O₂(g)

3. Mole ratio

Write the ratio of the coefficients of the substances that are object of the problem:

$2molHgO/1molO_2$

4. Calculate the number of moles of O₂(g)

Use the equation for ideal gases:

$pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol$

5. Calculate the number of moles of HgO

$\dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO$

6. Convert to mass

mass = # moles × molar mass

molar mass of HgO: 216.591g/mol

mass = 0.315mol × 216.591g/mol = 68.3g

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3 years ago

An evil villain wants to broadcast a message to everyone on Earth. They are using satellites for the communication process. For

stira [4]

Uhhhhhhh maybe the answer is 3

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2 years ago

How many grams of water will form if 10.54 g H2 react with 95.10 g O2?

sergeinik [125]

Answer:

94.0

Explanation:

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3 years ago

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How

labwork [276]

First convert grams to moles using molar mass of butane that is 58.1 g

3.50g C4H10 x (1 mol C4H10)/(58.1g C4H10) = 0.06024 mol C4H10 

Now convert moles to molecules by using Avogadro’s number

0.06024 mol C4H10 x (6.022x10^23 molecules C4H10)/(1 mol C4H10) = 3.627x10^22 molecules C4H10

And there are 4 carbon atoms in 1 molecule of butane, so use the following ratio:

3.627 x 10^22 molecules C4H10 x (4 atoms C)/(1 molecule C4H10)
= 1.45 x 10^23 atoms of carbon are present

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3 years ago

Read 2 more answers

Iron chloride + sodium hydroxide

patriot [66]

Answer:

Sodium hydroxide reacts with iron(III) chloride to produce iron(III) hydroxide and sodium chloride.

Hope this helps plz hit the crown :D

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3 years ago