MFe: 56 g/mol
..........
56g ----- 1 mol
5g ------- X
X = 5/56 = 0,089 moles of Fe
56g ----- 6,02×10²³ atoms
5g ------- X
X = (5×6,02×10²³)/56
X = 0,5375×10²³ = 5,375×10²² atoms of Fe
:•)
Answer:
67.5 atm
Explanation:
To answer this problem we can use <em>Boyle's law</em>, which states that at constant temperature the pressure and volume of a gas can be described as:
P₁V₁=P₂V₂
In this case:
P₁ = 101.3 atm
V₁ = 0.500 L
P₂ = ?
V₂ = 0.750 L
We input the data:
101.3 atm * 0.500 L = P₂ * 0.750 L
And solve for P₂:
P₂ = 67.5 atm
0.06 has one significant figure (unless there are zeros written after it). So I would round the result to 6000. Some teachers prefer at least 2 significant figures though.
First we need to find the number of moles that 43.9g of gallium metal is. We can do this by finding the molar weight of gallium and cross-multiplying to cancel out units:
So we are dealing with 0.63 moles of gallium metal.
We can take from the balanced equation that 4 moles of gallium metal will react completely with 3 moles of oxygen gas. We can take this ratio and make a proportion to find the amount of oxygen gas, in moles, that will react completely with 0.63 moles of gallium metal:
Cross multiply and solve for x:
So now we know that 0.47 moles of oxygen gas will react with 43.9g of gallium metal.
Nitrogen has 5 electrons in its valence level