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prisoha [69]
3 years ago
8

If Jesse cen make 41 jumps in 10 seconds how many can she do in five minutes.

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
1230 in five minutes  Just multiply 6 * 41 to get to minutes format, then multiply by five make it five minutes. To get the second answer just divide it by two, which would make it 615.


Hope this helps!
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Write the linear inequality in slop-intercept form. 4x - 6y ≥ 16
Pachacha [2.7K]
2/3x -8/3 >= y is the answer
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4 years ago
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You are organizing a pet show. Forty dogs will be shown the first morning. Four minutes will be allowed for each dog to be shown
Advocard [28]
There's 40 dogs and each gets 5 minutes. 40 times 5 is 200. The morning so will be 200 minutes or 3 hours and 20 minutes
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3 years ago
Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.
Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{1599\text{ years}}

k=4.33\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 1000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=5.19g

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 4.33\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = 10000 years

a = initial amount of the reactant  = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}

a-x=0.105g

Thus, the amount after 10000 years will be, 0.105 grams.

4 0
3 years ago
Graph the image of this figure after a dilation with a scale factor of 1/3 centered at the origin.
posledela

Answer:

see attached diagram

Step-by-step explanation:

A dilation with a scale factor of \dfrac{1}{3} centered at the origin has a rule:

(x,y)\mapsto\left(\dfrac{x}{3},\dfrac{y}{3}\right).

Then the image of the triangle ABC is triangle DEF(see attached diagram) with coordinates

  • D\left(\dfrac{-3}{3},\dfrac{3}{3}\right)\Rightarrow D(-1,1);
  • E\left(\dfrac{3}{3},\dfrac{9}{3}\right)\Rightarrow E(1,3);
  • F\left(\dfrac{6}{3},\dfrac{6}{3}\right)\Rightarrow F(2,2).

3 0
3 years ago
Saul has 8 bags. He records the weight of each bag on the line plot.
Naddika [18.5K]

Answer:

24

Step-by-step explanation:

just MultiplMultiply 8 times 3 and 24

8 0
2 years ago
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