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3 years ago

If Jesse cen make 41 jumps in 10 seconds how many can she do in five minutes.

1 answer:

6 0

1230 in five minutes Just multiply 6 * 41 to get to minutes format, then multiply by five make it five minutes. To get the second answer just divide it by two, which would make it 615.

Hope this helps!

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Write the linear inequality in slop-intercept form. 4x - 6y ≥ 16

Pachacha [2.7K]

2/3x -8/3 >= y is the answer

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4 years ago

Read 2 more answers

You are organizing a pet show. Forty dogs will be shown the first morning. Four minutes will be allowed for each dog to be shown

Advocard [28]

There's 40 dogs and each gets 5 minutes. 40 times 5 is 200. The morning so will be 200 minutes or 3 hours and 20 minutes

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3 years ago

Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago

Graph the image of this figure after a dilation with a scale factor of 1/3 centered at the origin.

posledela

Answer:

see attached diagram

Step-by-step explanation:

A dilation with a scale factor of $\dfrac{1}{3}$ centered at the origin has a rule:

$(x,y)\mapsto\left(\dfrac{x}{3},\dfrac{y}{3}\right).$

Then the image of the triangle ABC is triangle DEF(see attached diagram) with coordinates

$D\left(\dfrac{-3}{3},\dfrac{3}{3}\right)\Rightarrow D(-1,1);$
$E\left(\dfrac{3}{3},\dfrac{9}{3}\right)\Rightarrow E(1,3);$
$F\left(\dfrac{6}{3},\dfrac{6}{3}\right)\Rightarrow F(2,2).$

3 0

3 years ago

Saul has 8 bags. He records the weight of each bag on the line plot.

Naddika [18.5K]

Answer:

Step-by-step explanation:

just MultiplMultiply 8 times 3 and 24

8 0

2 years ago