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3 years ago

8

If Jesse cen make 41 jumps in 10 seconds how many can she do in five minutes.

1 answer:

Aleks04 [339]3 years ago

6 0

1230 in five minutes Just multiply 6 * 41 to get to minutes format, then multiply by five make it five minutes. To get the second answer just divide it by two, which would make it 615.

Hope this helps!

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6. The functions off and g are defined by f(x) = 4x + 2 and g(x) = x². Calculate for:

likoan [24]

Answer:

$\boxed{66}$

Step-by-step explanation:

$if \: the \: question \: is \: f[g(4)] \\ then \: at \: first \: solve \: for \: g(4) \\ g(4) = {4}^{2} \\ f[g(4)] = 4( {4}^{2} ) + 2 \\ f[g(4)] = 4(16) + 2 \\ f[g(4)] =64 + 2 \\ f[g(4)] = \boxed{66}$

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3 years ago

Between which two consecutive integers does ???147 lie?

BartSMP [9]

If those question marks are supposed to be a radical, then 12 and 13. The square root of 147= 12.12, which puts it between 12 and 13.

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3 years ago

What is the solution of log (2t+4) = log (14+3t)

egoroff_w [7]

See the attachment...

4 0

2 years ago

How many ml of 20 percent acid should be added to pure acid to make 70 ml of 30 percent acid?

Novay_Z [31]

Answer:

61.25%

Step-by-step explanation:

How many ml of 20 percent acid should be added to pure acid

to make 70 ml of 30 percent acid?

:

let x = amt of 20% mixture

then

(70-x) = amt of pure acid

:

0.20x + (70-x) =0 .30(70)

0.20x + 70 - x = 21

= 21 - 70

-0.8x =-49

x = 61.25%

x = +61.25 ml of 20% stuff

8 0

3 years ago

What equation represents the model shown below?

g100num [7]

Given:

The algebra tiles of an equation.

To find:

The equation represented by the given model.

Solution:

On the left side of the model we have 4 tiles of (-x) and 3 tiles of (-1). So,

$LHS=(-x)+(-x)+(-x)+(-x)+(-1)+(-1)+(-1)$

$LHS=-4x+(-3)$

$LHS=-4x-3$

On the right side of the model we have 8 tiles of (-1). So,

$RHS=(-1)+(-1)+(-1)+(-1)+(-1)+(-1)+(-1)+(-1)$

$RHS=-8$

Now, equate the LHS and RHS to get the equation.

$-4x-3=-8$

Therefore, the equation for the given model is $-4x-3=-8$ .

7 0

3 years ago