Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
Answer:
brain
Step-by-step explanation:
brain to the fullest
The expected value of y when x is equals to 45 in the equation is 35.06
<h3>How to find variable from an equation?</h3>
The equation is given as follows;
y = -2.61x + 152.51
where
- x = variable 1
- y = variable 2
Therefore,
when
x = 45
y = -2.61x + 152.51
y = -2.61(45) + 152.51
y = - 117.45 + 152.51
y = 35.06
learn more on equation here: brainly.com/question/14279419
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Answer: $257 per month
Explanation:
Pay = monthly payment
Set the total cost equal to number of months times payment per month (which you would leave as a variable because that’s what you’re solving for).
4,626 = 18P
Divide both sides by 18 because you’re trying to isolate the P.
4,626 = 18P —-> 257 = Pr
This leaves you with an evenly split number of 257.
<h3>Answer :- </h3>
<h3>Solution :- </h3>
- 2x + 42 = 90
- 2x = 90 - 42
- 2x = 48
- x = 48/2
- x = 24
<em>Hope</em><em> it</em><em> helps</em><em> </em><em>~</em>