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Aleksandr-060686 [28]
2 years ago
15

Help me find the surface area ​

Mathematics
1 answer:
Brut [27]2 years ago
6 0

Answer:

Step-by-step explanation:

area of triangular face = ½·3·4 = 6 cm²

area of 3 by 7 face = 3×7 = 21 cm²

area of 5 by 7 face = 5×7 = 35 cm²

area of 4 by 7 face = 4×7 = 28 cm²

total surface area = 2×6 + 21 + 35 + 28 = 96 cm²

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kylie bought a bunch of grapes that weighs 2 pounds and 9 ounces. How much did the grapes weigh in ounces only?
Grace [21]
Since 1 pound is 16 ounces, you would convert the 2 pounds to 32 ounces (16+16) and add the 32 ounces to the already given 9 ounces to get 41 ounces. (32+9)
Hope that helped.
7 0
2 years ago
Find the median, Q1, Q3, the IQR for the following
ELEN [110]
<span>24,24,28, 32,40,42
median = (28+32)/2 = 30
Q1 = 24
Q3 = 40
IQR = 40 -24 = 16</span>
4 0
3 years ago
Read 2 more answers
Find the interquartile range of the data.
SCORPION-xisa [38]
The correct answer is D.14.
The interquartile range is the difference between the Upper Quartile and the Lower Quartile of a data set.

By arranging the numbers in the stem and leaf plot from lowest to highest value, you get an even set of data (31,33,35,41,43,46,48,49,49,50). By dividing the set into two, you get a lower half of your data (31,33,35,41,43) and an upper half (46,48,49,49,50). The lower quartile is the median or the midpoint of the lower half of your data while upper quartile is for the upper half. The lower quartiles is 35 and upper quartile is 49. The difference between the two is 14.
8 0
3 years ago
Determine the sample size required to estimate the mean score on a standardized test within 4 points of the true mean with 98% c
Darina [25.2K]

Answer:

67

Step-by-step explanation:

You have to use fractions to show your work and I'm not going to do that but just know that it is the answer.

3 0
2 years ago
Pre cal/cal master needed
weqwewe [10]
Take x-2 and insert it into 2x^2 + 3x-2 where the x is located 
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2

Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2 
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2  =  x^2 -4x + 4
2(x-2)^2  =  2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8

Now that 2(x-2)^2 is done lets move on to 3(x-2).

Use the distributive property and distribute the 3
3(x-2) = 3x - 6

All that is left is the -2 

Now lets put it all together 
2(x-2)^2 + 3(x-2)-2

2x^2 - 8x + 8 + 3x - 6 - 2

Now combine all our like terms 
2x^2 - 8x + 8 + 3x - 6 - 2
Combine:  2x^2      =  2x^2 
Combine: -8x + 3x  =  -5x
Combine:  8 - 6 - 2 =   0

So all we have left is
2x^2 - 5x





5 0
3 years ago
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