A. 1:3
The equation shows that 1 mol Fe_3_O4 ≡ 3 mol Fe.
∴ The mole ratio is Fe_3_O4:Fe = 1:3.
“B. 1:4” is <em>incorrect</em>. It is the mole ratio of <em>Fe_3O_4:H_2O </em>and of<em> Fe_3O_4:H_2</em>.
“C: 3:1” is <em>incorrect</em>. It is the mole ratio of <em>Fe:Fe_3O_4</em>.
“D: 4:3” is <em>incorrect</em>. It is the mole ratio of <em>H_2O:Fe and of H_2:Fe</em>.
Answer:
0.4g/mL
Explanation:
The following data were obtained from the question:
Mass = 2g
Volume = 75 — 70 = 5mL
Density =?
Density = Mass /volume
Density = 2/5
Density = 0.4g/mL
The density of the substance is 0.4g/mL
Answer: 12.92g of CoSO4
Explanation:
Molar Mass of CoSO4 = 59 + 32 + (16x4) = 59 + 32 +64 = 155g/mol
Molarity of CoSO4 = 0.303mol/L
Mass conc. In g/L = Molarity x molar Mass
= 0.303x155 = 46.965g/L
275 grams of water = 0.275L of water
46.965g of CoSO4 dissolves in 1L
Therefore Xg of CoSO4 will dissolve in 0.275L i.e
Xg of CoSO4 = 46.965x0.275 = 12.92g
Therefore 12.92g of CoSO4 is needed
Answer:
Regarding Measures of center, the Mean will be smaller, and Median will not be affected. Thus, the median will not change, since the temperature was already low initially and only decreased. However, the median takes the average of all values into account, and if you substitute a value for a smaller value, the average decreases.
In relation to Measures of spread, the range and standard deviation will be larger, and the IQR will not change. Therefore, the range is the highest minus the lowest number; if the lowest number decreases sharply, the range increases. On the other hand, the IQR only counts the first and third quartile values. Therefore, since the value was already the lowest, if it is decreased, it will not change the IQR. However, the standard deviation will increase significantly, as the decreasing value of the lowest data point will increase the overall spread.
Explanation:
It is a compound machine i think, tell me if its right!
