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vova2212 [387]
3 years ago
7

Consider the balanced equation below.

Chemistry
1 answer:
pochemuha3 years ago
8 0

A. 1:3

The equation shows that 1 mol Fe_3_O4 ≡ 3 mol Fe.

∴ The mole ratio is Fe_3_O4:Fe = 1:3.

“B. 1:4” is <em>incorrect</em>. It is the mole ratio of <em>Fe_3O_4:H_2O </em>and of<em> Fe_3O_4:H_2</em>.

“C: 3:1” is <em>incorrect</em>. It is the mole ratio of <em>Fe:Fe_3O_4</em>.

“D: 4:3” is <em>incorrect</em>. It is the mole ratio of <em>H_2O:Fe and of H_2:Fe</em>.

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Why do unsaturated fatty acids have lower melting points than saturated fatty acids?
Alexus [3.1K]

The carbon = carbon double bonds in unsaturated fatty acids are restricting the movement of the molecule branches. They are more "kinked" up and do not pack as tightly. whereas, saturated fatty acids have more freedom of movement and tend to pack together better. Therefore, in the case of unsaturated fatty acids they can not compact tightly together and there are less van der Waals interactions between the molecules, and so the melting point is reduced.

3 0
4 years ago
A sample of an unknown compound is vaporized at 130°C . The gas produced has a volume of 1280mL at a pressure of 1.00 atm and it
loris [4]
This is an ideal gas law question. It uses the ideal gas law equation, PV =nRT.
P = pressure, V = volume, n = moles, R is the constant, and T is temperature in kelvin. The temperature needs to be converted Kevin first. To convert from Celsius to Kevin, you add 273, meaning that the temp in Kevin is 403K. Then plug all the info into the equation to solve for moles.
(1.00atm)(1.280L)=n(0.0821)(403K)
n = 0.0387moles

To find molar mass, divide mass by moles.

4.03g / 0.0387moles = 104.17g/mol

104g/mol rounded to three significant digits
8 0
3 years ago
Is caesium a solid liquid or gas​
noname [10]

Answer:

solid

Explanation:

5 0
3 years ago
Read 2 more answers
How to solve for K when given your anode and cathode equations and voltage
Aleks04 [339]

Answer:

See Explanation

Explanation:

In thermodynamics theory the Free Energy (ΔG) of a chemical system is described by the expression ΔG = ΔG° + RTlnQ. When chemical system is at equilibrium ΔG = 0. Substituting into the system expression gives ...

0 = ΔG° + RTlnKc, which rearranges to ΔG° = - RTlnKc.  ΔG° in electrochemical terms gives ΔG° = - nFE°, where n = charge transfer, F = Faraday Constant = 96,500 amp·sec and E° = Standard Reduction Potential of the electrochemical system of interest.

Substituting into the ΔG° expression above gives

-nFE°(cell) = -RTlnKc => E°(cell) = (-RT/-nF)lnKc = (2.303·R·T/n·F)logKc

=> E°(cell) = (0.0592/n)logKc = E°(Reduction) - E°(Oxidation)

Application example:

Calculate the Kc value for a Zinc/Copper electrochemical cell.

Zn° => Zn⁺² + 2e⁻  ;    E°(Zn) = -0.76 volt  

Cu° => Cu⁺² + 2e⁻ ;    E°(Cu) =  0.34 volt

By natural process, charge transfer occurs from the more negative reduction potential to the more positive reduction potential.

That is,

           Zn° => Zn⁺² + 2e⁻ (Oxidation Rxn)

Cu⁺² + 2e⁻ => Cu°             (Reduction Rxn)

E°(Zn/Cu) = (0.0592/n)logKc

= (0.0592/2)logKc = E°(Cu) - E°(Zn) = 0.34v - (-0.76v) = 1.10v

=> logKc = 2(1.10)/0.0592 = 37.2

=> Kc = 10³⁷°² = 1.45 x 10³⁷

3 0
3 years ago
N2+3H2—&gt; 2NH3 What volume of NH3 at STP is produced if 25.0g of N2 is reacted with an excess of H2 ?
Butoxors [25]

Answer:

The answer to your question is 40 L of NH₃

Explanation:

Data

Volume of NH₃ = x

mass of N₂ = 25 g

mass of H₂ = excess

Balanced chemical reaction

                     N₂  +  3H₂   ⇒  2NH₃

Process

1.- Find the molar mass of N₂ and NH₃

N₂ = 14 x 2 = 28g

2NH₃ = 2[ 14 + 3] = 34 g

2.- Write a proportion to solve this problem

                    28 g of N₂ --------------- 34 g of NH₃

                     25 g of N₂ -------------   x

                     x = (25 x 34)/28

                     x = 30.36 g of NH₃

3.- Calculate the volume of NH₃

                     17 g of NH₃ -------------- 22.4 L

                     30.36 g of NH₃ --------  x

                     x = (30.36 x 22.4) / 17

                     x = 40 L

6 0
3 years ago
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