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3 years ago

Consider the balanced equation below.

Chemistry

1 answer:

pochemuha3 years ago

8 0

A. 1:3

The equation shows that 1 mol Fe_3_O4 ≡ 3 mol Fe.

∴ The mole ratio is Fe_3_O4:Fe = 1:3.

“B. 1:4” is incorrect. It is the mole ratio of Fe_3O_4:H_2O and of Fe_3O_4:H_2.

“C: 3:1” is incorrect. It is the mole ratio of Fe:Fe_3O_4.

“D: 4:3” is incorrect. It is the mole ratio of H_2O:Fe and of H_2:Fe.

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The solubility of water in diethyl ether has been reported to be 1.468 % by mass.' Assuming that 23.0 mL of diethyl ether were a

melomori [17]

Explanation:

As it is given that solubility of water in diethyl ether is 1.468 %. This means that in 100 ml saturated solution water present is 1.468 ml.

Hence, amount of diethyl ether present will be calculated as follows.

(100ml - 1.468 ml)

= 98.532 ml

So, it means that 98.532 ml of diethyl ether can dissolve 1.468 ml of water.

Hence, 23 ml of diethyl ether can dissolve the amount of water will be calculated as follows.

Amount of water = $\frac{1.468 ml \times 23 ml}{98.532 ml}$

= 0.3427 ml

Now, when magnesium dissolves in water then the reaction will be as follows.

$Mg + H_{2}O \rightarrow Mg(OH)_{2}$

Molar mass of Mg = 24.305 g

Molar mass of $H_{2}O$ = 18 g

Therefore, amount of magnesium present in 0.3427 ml of water is calculated as follows.

Amount of Mg = $\frac{24.305 g \times 0.3427 ml}{18 g}$

= 0.462 g

6 0

3 years ago

Calculate the hydroxide ion consentration of a solution with pH = 3.25. show all calculations leading to your answer.

lidiya [134]

First you calculate the pOH of the solution:

pH+ pOH = 14

3.25 + pOH = 14

pOH = 14 - 3.25

pOH = 10.75

Concentration of [OH]⁻ in solution:

[ OH⁻ ] = $10 ^{-pOH}$

[ OH⁻ ] = 10^ - 10.75

[OH⁻] = 1.778 x 10⁻¹¹ M

hope this helps !

6 0

3 years ago

What is the answer to the net ionic equation FeO(s)+2HClO4(aq)--> Fe(ClO4)2 (aq)+ H2O(l)

yan [13]

Feo + 2H = H2O + Fe + 2 + CIO4-
this is ur answer. .
mrk me as brainlist

8 0

3 years ago

Read 2 more answers

Balance the following reactions using either the oxidation number method or the half-reaction method. Identify which element has

Marina86 [1]

$6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO_3^- + 3H_2O$ is the balanced chemical equation.

<h3>What is a balanced chemical equation?</h3>

A balanced chemical reaction is an equation that has equal numbers of each type of atom on both sides of the arrow.

Half-reaction method:

Unbalanced chemical equation:

$Ce^{4+} + I^-$ → $Ce^{3+} + IO^{3-}$

Oxidation half-reaction:

$I^-+ 6OH^- - 6e-$ → I $O^{3-} + 3H_2O$

Reduction half-reaction:

$Ce4^+ + e^-$ → $Ce^{3+}$

Balanced chemical equation:

$6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO^{3-} + 3H_2O$

Oxidation number method:

Unbalanced chemical equation:

$Ce^{4+} + I^-$ → $Ce^{3+} + IO^{3-}$

$I^{-1} -6e^-$ → $I^{+5}$

$Ce^{4+} + e^-$ → $Ce^{3+}$

Balanced chemical equation:

$6Ce^{4+} + I^{-1}$ → $6Ce^{3+} + I^{+5}$

$6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO_3^- + 3H_2O$

Hence, $6Ce^{4+} + I^- + 6OH^-$ → $6Ce^{3+} + IO_3^- + 3H_2O$ is the balanced chemical equation.

Learn more about the balanced chemical equation here:

https://brainly.in/question/46754758

#SPJ1

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2 years ago

the pressure in a sealed can of gas is 235 kPa when it sits at room temperature 293k. if the van is warmed to 321K what will the

Katyanochek1 [597]

Answer:

hard one

Explanation:

7 0

3 years ago