They have the same amounts of electrons
Answer:
3.75 * 10^7 g of this water would have been consumed.
Explanation:
ppm represents parts per million.
ppm = (mass solute / mass solution ) *10^6
⇒It is a way to express the concentration of very dilute solutions.
For this situation we have:
ppm = (grams of mercury / grams of solution ) * 10^6
0.004 = (x grams of mercury / 1g of solution) 10^6
x = 0.004 /10^6
x = 4 *10^-9 g Mercury
This mass of mercury is per gram of solution. In the next step, we can calculate the amount of solution (water plus mercury) that would have to be ingested to ingest 0.150 g of mercury
0.150 g of Hg * (1g of solution/ 4 *10^-9 g Mercury)= 3.75 *10^7
3.75 * 10^7 g of this water would have been consumed.
Answer:
Na + CaSO4 = Na2SO4 + Ca
Explanation:
single displacement (substitution)
Answer:
5
Explanation:
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When the first reaction equation is:
AgI(S) ↔ Ag+(Aq) + I-(Aq)
So, the Ksp expression = [Ag+][I-]
∴Ksp = [Ag+][I-] = 8.3 x 10^-17
Then the second reaction equation is:
Ag+(aq) + 2NH3(aq) ↔ Ag(NH3)2+
So, Kf expression = [Ag(NH3)2+] / [Ag+] [NH3]^2
∴Kf = [Ag(NH3)2+] /[Ag+] [NH3]^2 = 1.7 x 10^7
by combining the two equations and solve for Ag+:
and by using ICE table:
AgI(aq) + 2NH3 ↔ Ag(NH3)2+ + I-
initial 2.5 0 0
change -2X +X +X
Equ (2.5-2X) X X
so K = [Ag(NH3)2+] [I-] / [NH3]^2
Kf * Ksp = X^2 / (2.5-2X)
8.3 x 10^-17 * 1.7 x10^7 = X^2 / (2.5-2X) by solving for X
∴ X = 5.9 x 10^-5
∴ the solubility of AgI = X = 5.9 x 10^-5 M
