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Angelina_Jolie [31]
4 years ago
15

The Richter scale is used for measuring the magnitude of an earthquake. The Richter magnitude is given R = 0.67log(0.37E) + 1.46

where E is the energy (in kilowatt hours) released by the earthquake. If an earthquake release 15,500,000,000 kilowatt hours of energy, what is the earthquake's magnitude?
Mathematics
1 answer:
natka813 [3]4 years ago
7 0

Answer:

7.9982

Step-by-step explanation:

-The function for an earthquake's magnitude is given by  R = 0.67log(0.37E) + 1.46

-E is energy in kwh.

#For 15,500,000,000 kilowatt hours the magnitude would be:

R = 0.67\ log(0.37E) + 1.46,\ \  E=15,500,000,000  \ kwh\\\\\therefore R=0.67 \ log(0.37\times 15,500,000,000)+1.46\\\\\\=7.9982

Hence, the earthquakes magnitude is 7.9982

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Used distributive property: a(b + c) = ab + ac
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If Richard can paint their living room in 4 hours, and Vanessa can paint the same living room in 5 hours, then how long will it
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Step-by-step explanation:

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(5 + 4)/20. ( find the LCM)

9/20 = 1/y

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4 0
4 years ago
Given the set of integers 1-10,what,is the probability of selecting a number that is divisble by 3
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Write the extreme and middle terms of 5 : 80 :: 4 :64
Stells [14]

Answer:

The extremes are 5 and 64.

The middle terms are 80 and 4.

Step-by-step explanation:

Given the proportion:

5 : 80 :: 4 :64

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The extreme and middle terms of the given proportion.

Solution:

The given statement is in proportion if and only if the product of extremes i.e. the numbers at both the ends is equal to the product of middle numbers.

OR

First number \times Fourth number = Second number \times Third number

First of all, let us check the two products.

5 \times 64 = 320

And the second product:

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The product is same therefore, the given numbers are in proportion.

The extreme terms are the first and the fourth numbers.

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7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bcos%2030%7D%7B1%2Bsin30%7D%3Dtg30" id="TexFormula1" title="\frac{cos 30}{1+sin30}=tg
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\cos 30=\frac{\sqrt{3}}{2}

\sin 30 = \frac{1}{2}

\tan 30=\frac{1}{\sqrt{3}}

Now we insert that into the equation:

\dfrac{\frac{\sqrt{3}}{2}}{1+\frac{1}{2}} = \frac{1}{\sqrt{3}}

\dfrac{\frac{\sqrt{3}}{2}}{\frac{3}{2}} = \frac{1}{\sqrt{3}}

\frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}

\frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}}\cdot \frac{\sqrt{3}}{\sqrt{3}}\\

\frac{\sqrt{3}}{3} = \frac{\sqrt{3}}{\sqrt{3}\cdot \sqrt{3}}\\

\frac{\sqrt{3}}{3} = \frac{\sqrt{3}}{3}

6 0
4 years ago
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