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frutty [35]
3 years ago
13

Can I get some help with this problem ​

Mathematics
1 answer:
Andrej [43]3 years ago
5 0

Answer:

I cant give you the answer but I do know that you need a compass to solve this. ( the first corner is 70degrees)

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A tiny songbird called the blackpoll warbler migrates each fall from North America. A tracking study showed one bird flew from V
Alexus [3.1K]

Answer:

<h3>2642km</h3>

Step-by-step explanation:

Given the map coordinates o a bird during travel from Vermont at cordinate (63,45) toto Venezuela at map coordinates (67,10). In order to know how far the bird has travelled, we need to find the distance between the two coordinates first using the formula;

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given x₁ = 63, y₁ = 45, x₂ = 67, y₂ = 10

D =\sqrt{(67-63)^2+(10-45)^2}\\ \\D = \sqrt{4^2+(-35)^2} \\\\D = \sqrt{16+1225} \\\\D = \sqrt{1241} \\\\D = 35.2278

If each map coordinate represents 75 kilometers, then the birds distance in km will be 75*35.2278 = 2642.087km

Hence the birds distance in km will be 2642km to the nearest kilometers

4 0
3 years ago
A circle has a diameter of 14 feet. What is the circumference of the circle? Use 3:14 for pie.
Marianna [84]

Answer:

Circumference= 43.96 feet

Step-by-step explanation:

Diameter of the circle= 14 feet

Radius of the circle= 14/2= 7 feet

Circumference of the circle= 2\pi r

As, \pi =\frac{22}{7}=3.14

Circumference:

                          =2*3.14*7\\\\=3.14*14\\\\=43.96feet

The circumference of the circle with the radius= 7 feet is 43.96 feet

6 0
3 years ago
Solve for z.<br><br> z12≤3<br><br> z≥36<br><br> z≤36<br><br> z≥4<br><br> z≤4
erastova [34]

Answer:

Your answer is correct... it's no.3 ... but if you multiply a inequality by a negative value the inequality sign changes.. like if you habe greater than it'll be less than... Keep that in mind too

5 0
3 years ago
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Sabrina should be careful of those ants and bees.
5 0
3 years ago
WILL MARK BRAINLIEST HELPPP ME
steposvetlana [31]

Answer:

x=47

Step-by-step explanation:

5 0
3 years ago
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