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zepelin [54]
3 years ago
10

I need help with this problem

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
6 0
-24 + y= -120

y= -96 is the answer to the problem
ANEK [815]3 years ago
5 0
Y= -124
-6+y/4=-30
multiple by four on each side
-6+y=-120
add 6 to each side
y=-124
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6% is less than 1, so it can't be any whole number.
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A store had 150 laptops in the month of January. Every month, 20% of the laptops were sold and 10 new laptops were stocked in th
Softa [21]

<u>Answer-</u>

\boxed{\boxed{f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0}}

<u>Solution-</u>

Here, n represents the number of months and f(n) represents the number of laptops in the store after n months.

As the store had 150 laptops in the month of January or at the beginning.

So f(0)=150

Every month, 20% of the laptops were sold and 10 new laptops were stocked in the store.

As 20% of laptops were sold, so 80% were in the store.

So, after one month total number of laptops in the store,

\Rightarrow f(1)=0.8(150)+10

\Rightarrow f(1)=0.8(f(0))+10     (\because f(0)=150)

Again after one month total number of laptops in the store,

\Rightarrow f(2)=0.8\times (0.8(150)+10)+10

\Rightarrow f(2)=0.8(f(1))+10     (\because f(1)=0.8(150)+10)

Analyzing the pattern, the recursive function f(n) will be,

f(n)=0.8(f(n-1))+10,\ f(0)=150,\ \ n>0


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Radius = diameter/2

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Which of the following decimals is equivalent to three and ten hundredths
Montano1993 [528]

Answer: 3.1 or 3.10

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3 and 10 hundredths = 3 + 10/100 = 3 + 0.10

3.10 / 3.1

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Calculation for the probability of getting a sample average of 1.8 or less

Using this formula

z score =(X-mean)/Standard errror

Where,

Standard error =Standard deviation/√(n)

Let plug in the formula

P(Xbar<1.8)=P(Z<(1.8 hours per day -2.2 hours per day)/(2 hours /√(200))

P(Xbar<1.8)=P(Z<-0.4/(2/14.14))

=P(Z<-0.4/0.1414)

=P(Z<-2.83)

Now let find the Z score of P(Z<-2.83) using the z table

P=0.0023

Therefore the probability of getting a sample average of 1.8 or less is:0.0023

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