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2 years ago

I forgot how to do this. please give me a example on how i do this thank u

Mathematics

1 answer:

nydimaria [60]2 years ago

4 0

Answer:

$t \in \mathrm {R}$

Step-by-step explanation:

$2t + 6 = 2(t + 3)$

$2t + 6 = 2t + 6$

$2t + 6 - 2t = 2t - 6 - 2t$

$6 = 6$

$t \in \mathrm {R}$

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Please help me. Show work

Goryan [66]

What hell there is nothings ??

7 0

2 years ago

for a recipe Peter uses 2 cups of sugar for every 3 cups of flour which table shows equivalent ratios for this table

Novosadov [1.4K]

Answer:

4 to 6

Step-by-step explanation:

if you do 2 times 2 which is 4 then you do 3 times which is 6 then you get your answer

4 0

3 years ago

A rectangular piece of paper has a width that is 3 inches less than its length. It is cut in half along a diagonal to create two

saul85 [17]

Answer:

I think the answer is right.isn't The rectangle width 8 and length 11 inches

3 0

3 years ago

Read 2 more answers

How do u factor this

PilotLPTM [1.2K]

You can factor a parabola by finding its roots: if

$p(x)=x^2+bx+c$

has roots $x_1,\ x_2$ , then you have the following factorization:

$p(x) = (x-x_1)(x-x_2)$

In order to find the roots, you can use the usual formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In the first example, this formula leads to

$x_{1,2} = \dfrac{-2\pm\sqrt{4+4}}{2} = \dfrac{-2\pm\sqrt{8}}{2} = \dfrac{-2\pm2\sqrt{2}}{2} = 1 \pm \sqrt{2}$

So, you can factor

$x^2-2x-1 = (x-1-\sqrt{2})(x-1+\sqrt{2})$

The same goes for the second parabola.

As for the third exercise, simply plug the values asking

$f(1.5)=-5.25$

you get

$f(-1.5) = 1.5c-3 = -5.25$

Add 3 to both sides:

$1.5c = -2.25$

Divide both sides by 1.5:

$c = 1.5$

7 0

3 years ago

Pythagorean Theorem Word

diamong [38]

Answer:

40 miles

Step-by-step explanation:

In the attached diagram, Point A is the starting point and C is the end point. We want to determine the distance from A to C.

The path driven forms a right triangle in which AC is the hypotenuse.

We therefore use the<u> Pythagorean Theorem</u> to solve for the AC.

Pythagorean Theorem: $Hypotenuse^2=Opposite^2+Adjacent^2$

$|AC|^2=32^2+24^2\\|AC|^2=1600\\|AC|=\sqrt{1600}\\ |AC|=40$ miles$

The straight line distance from the starting point is 40 miles.

7 0

3 years ago