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Trava [24]
3 years ago
12

If the data below were represented by a comparative bar chart, the bar

Mathematics
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

b right handed boys

Step-by-step explanation:

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3x+10+x solve for x thank you :)
weeeeeb [17]

Answer:

4x + 10

Step-by-step explanation:

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Last one i think if not i will post the last one this is confusing
maria [59]

Answer: 23

Step-by-step explanation: Because you do 34-11

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3 years ago
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Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
stealth61 [152]

Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
3 years ago
Read 2 more answers
Write the equation of the line containing the points (3, 6) and (7, - 2) in standard form.
Rama09 [41]

Answer:

y = mx + c \\ 6 = 3m + c...(1) \\  - 2 = 7m + c...(2) \\ subtract \: (2) - (1) \\ 4m =  - 8 \\  \therefore \: m  = - 2 \: sub \: in \: (1) \\ 6 = 3( - 2) + c \\ \therefore \: c  = 12 \\  \boxed{y =  - 2x + 12}

7 0
2 years ago
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From a group of 3 men and 4 women, a delegation of 2 is selected. What is the expected number of men in the delegation?
Ostrovityanka [42]

Answer:

The expected number of men in the delegation is 0.86.

Step-by-step explanation:

Number of men = 3

Number of women = 4

A delegation of 2 is selected.

Let X be the number of men selected. So, the possible values of X are 0,1,2.

P(X=0)=\dfrac{^3C_0\times ^4C_2}{^7C_2}=\dfrac{2}{7}

P(X=1)=\dfrac{^3C_1\times ^4C_1}{^7C_2}=\dfrac{4}{7}

P(X=2)=\dfrac{^3C_2\times ^4C_0}{^7C_2}=\dfrac{1}{7}

The expected number of men in the delegation is

E(x)=0\times P(X=0)+1\times P(X=1)+2\times P(X=2)

E(x)=0\times \dfrac{2}{7}+1\times \dfrac{4}{7}+2\times \dfrac{1}{7}

E(x)=\dfrac{6}{7}

E(x)\approx 0.86

Therefore, the expected number of men in the delegation is 0.86.

4 0
3 years ago
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