The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
Answer:
The answer to 75 - ( 8 + 45 ÷ 3 ) × 2= 29
I blieve answer is A........mmmmmmmmmmmm
Answer:
(0.5, 4 )
Step-by-step explanation:
Given the 2 equations
2x + 3y = 13 → (1)
4x - y = - 2 → (2)
Multiplying (2) by 3 and adding to (1) will eliminate the term in y
12x - 3y = - 6 → (3)
Add (1) and (3) term by term to eliminate y
14x = 7 ( divide both sides by 14 )
x = 0.5
Substitute x = 0.5 into either of the 2 equations and evaluate for y
Substituting into (1)
2(0.5) + 3y = 13
1 + 3y = 13 ( subtract 1 from both sides )
3y = 12 ( divide both sides by 3 )
y = 4
Solution is (0.5, 4 )
