What is the basic unit that represents quantum nature of electricity?
1 answer:
The basic unit that represents the quantum nature of electricity is the charge of the electron, represented with the symbols 
, which corresponds to
The quantum nature of electricity was demonstrated for the first time by Millikan, in its oil drop experiment. In this experiment, Millikan put charged oil drops between two metallic plates, applying a potential difference across them, such that the electrical force acting on the drops was in balance with their weight. Knowing the intensity of the electric field and the mass of the drops, he was able to determine the charge of the oil drops, and he found that this charge was always an integer multiple of a certain value, exactly.
The quantum nature of electricity was demonstrated for the first time by Millikan, in its oil drop experiment. In this experiment, Millikan put charged oil drops between two metallic plates, applying a potential difference across them, such that the electrical force acting on the drops was in balance with their weight. Knowing the intensity of the electric field and the mass of the drops, he was able to determine the charge of the oil drops, and he found that this charge was always an integer multiple of a certain value, exactly
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Answer:
30.22 hours
Explanation:
Given data:
A= l² = (2 x )² = 4 x
m²
Length 'L' = 5m
current '' = 2 A
density of free electrons 'n'= 8.5 x /m³
Current Density 'J' = / A
J= 2/4 x
J= 5 x A/m²
We can determine the time required for an electron to travel the length of the wire by
T= L/ Vd
Where,
L is length and Vd is drift velocity.
Vd can be defined by J/ n|q|
where,
n is the charge-carrier number density
|q| is is the charge carried by each charge carrier
=>1.6 x C
T= L/ Vd
Therefore,
T= L . n|q| / J
T= (4 x 8.5 x x |1.6 x
|)/5 x
T= 108800 seconds =>1813.33 minutes
Converting minute into hours:
T= 30.22 hours
Thus, time that is required for an electron to travel the length of the wire is 30.22 hours
Answer:
The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
Explanation:
The first figure that I copy here with is the figure corresponding to this question.
The thumb is pointing upward.
The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.
The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.
So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.
The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.
Explanation:
The first figure that I copy here with is the figure corresponding to this question.
The thumb is pointing upward.
The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.
The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.
So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.