A train travels 70 kilometers in 1 hours, and then 63 kilometers in 2 hours. What is its average speed?
1 answer:
The answer is: " 44 
km " ;
or; write as: " 44.333 km " .
___________________________________________________________
Explanation:
___________________________________________________________
(70 km + 63 km) ÷ (2 + 1 ) = 133 km ÷ 3 = " 44 km " ;
or; write as: " 44.333 km " .
___________________________________________________________
or; write as: " 44.333 km " .
___________________________________________________________
Explanation:
___________________________________________________________
(70 km + 63 km) ÷ (2 + 1 ) = 133 km ÷ 3 = " 44
or; write as: " 44.333 km " .
___________________________________________________________
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Answer:
part(a) 151 m
part(b) 1.073 m/s2
part(c) 16.7 secs
Explanation:Firstly the person applied brakes 0.5 secs after seeing the red light hence the distance traveled during this time is
d=v*t
d=18*0.5
d=9m
For part (a)
I have corrected this question and now
The person was 160m from the intersection before applying the brakes as he traveled 9m before the brakes
He is now 151 m from intersection as
s=160-9
s= 151 m
part (b)
As it is given that velocity of the car is 0 at the intersection so we use this information in kinematic equation
here u=18m/s and s=151
To calculate time we can use the acceleration equation
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Area =
=
=
= m
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For drop, n =
For B drop, n =
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=
= 1.5
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