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defon
3 years ago
7

You are on roller blades on top of a small hill. Your potential energy is equal to 1,000.0 joules. The last time

Physics
1 answer:
olga2289 [7]3 years ago
3 0
A) The weight of a person is given by:
W=mg
where m is the mass of the person and g is the gravitational acceleration. In this problem, the mass of the person is m=60.0 kg, while the value of g is g=9.81 m/s^2, therefore the weight of the person is 
W=(60 kg)(9.81 m/s^2)=588.6 N

b) The gravitational potential energy at the top of the hill is U=1000 J. The potential energy is also given by the product between the weight W and the height of the hill h:
U=Wh
If we rearrange the equation, we can calculate the height of the hill, h: 
h= \frac{U}{W} = \frac{1000 J}{588.6 N} =1.70 m

c) At the bottom of the hill, all the potential energy at the top of the hill has converted into kinetic energy:
U=K
U= \frac{1}{2} mv^2
where m is the mass and v is the speed. If we rearrange the formula, we can calculate the speed at the bottom of the hill:
v=\sqrt{\frac{2U}{m}}=\sqrt{\frac{2\cdot 1000 J}{60.0 kg}}=5.8 m/s
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Answer:

t = 0.657 s

Explanation:

given,

initial vertical velocity = 7.5 m/s

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angle = 49◦

using kinetic equation

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final velocity in horizontal direction

v cosθ = u_x   + a_x × t

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Dividing equation (1) / (2)

tan \theta =\dfrac{u_y - gt}{a_x\times t}

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t = \dfrac{u_y}{tan \theta \times a_x + g}

u_y   =   initial velocity along x direction

acceleration along a_x = 1.4 m/s²

g = acceleration due to gravity   = 9.8 m/s²

θ = 43° ,   u_y   =  7.5 m/s    

t = \dfrac{7.5}{tan 49^0\times 1.4+ 9.8}

t = 0.657 s

time taken by the particle is t = 0.657 s

6 0
3 years ago
A man throw a ball vertically up word with an intial speed 20m/s. What is the maximum height rich by the ball and how long does
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Answer:

u=20 m/s, T=4s

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and time t can be determined by the formula

t=gv−u=−10−20=2s

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it is helpful for you

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