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3 years ago

¿Por qué cuando agrego cubos de hielo a un vaso de gaseosa, estos se derriten?

Physics

1 answer:

77julia77 [94]3 years ago

4 0

Answer:

Esto se debe a que la soda está más caliente que el hielo, lo que hace que pase por su punto de fusión.

Explanation:

Me enteré de esto durante la clase de ciencias hace un par de años. jajaja

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A hummingbird flies 1.2 m along a straight path at a height of 3.4 m above the ground. Upon spotting a flower below, the humming

Viefleur [7K]

Answer:1.84

Explanation:

Given

Humming bird travels 1.2 m along a straight line at height of 3.4 m

Now bird drops 1.4 m to hover in front of the flower

So bird net displacement is

displacement $=\sqrt{1.2^2+1.4^2}$

displacement $=\sqrt{3.4}$

=1.84

7 0

3 years ago

A long, rigid conductor, lying along an x axis, carries a current of 4.99 A in the negative x direction. A magnetic field is pre

Tcecarenko [31]

Answer with Explanation:

We are given that

Current in conductor=I=4.99 A (-x direction)

Magnetic field=B= $3.72\hat{i}+8.72x^2\hat{j}mT=(3.72i+8.72x^2j)\times 10^{-3}$

(1mT= $10^{-3} T$ )

x(in m) and B (in mT)

Length of conductor is given in negative x- direction

$\vec{L}=-x\hat{i}$

$dL=-dx\hat{i}$

Force on current carrying conductor is given by

$F=I(L\times B)$

$dF=I(dL\times B)$

Integrating on both sides then we get

$\vec{F}=\int_{1.41}^{2.77}(4.99)(-dx\hat{i}\times (3.72\hat{i}+8.72x^2\hat{j}))\times 10^{-3}$

$\vec{F}=-\int_{1.41}^{2.77}(4.99\times 10^{-3})\cdot 8.72(x^2\hat{k})dx$ ( $i\times i=0, i\times j=k$

$\vec{F}=-(4.99\times 10^{-3}\times 8.72)[\frac{x^3\hat{k}}{3}]^{2.77}_{1.41}$

$\vec{F}=-\frac{(4.99\times 10^{-3}\cdot 8.72)}{3}((2.77)^3-(1.41)^3)\hat{k}$

$\vec{F}=-0.268 \hat{k} N$

a. x- component of force=0

b.y- component of force=0

c.z- component of force=-0.268 N

5 0

3 years ago

The gravitational force exerted by a proton on an electron is 2x1039 times weaker than the electric force that the proton exerts

pickupchik [31]

To solve this problem we will rely on the theorems announced by Newton and Coulomb about the Gravitational Force and the Electrostatic Force respectively.

In the case of the Force of gravity we have to,

$F_g = G\frac{m_pm_e}{d^2}$

Here,

G = Gravitational Universal Constant

$m_p$ = Mass of Proton

$m_e$ = Mass of Electron

d = Distance between them.

$F_g = (6.673*10^{-11} kg^{-1} \cdot m^3 \cdot s^{-2}) (\frac{(1.672*10^{-27}kg)(9.109*10^{-31})}{(52.9pm)^2})$

$F_g = 3.631*10^{-47}N$

In the case of the Electric Force we have,

$F_e = k\frac{q_pq_e}{d^2}$

k = Coulomb's constant

$q_p$ = Charge of proton

$q_e$ = Charge of electron

d = Distance between them

$F_e = (9*10^9N\cdot m^2 \cdot C^{-2})(\frac{(1.602*10^{-19}C)(1.602*10^{-19}C)}{(52.9pm)^2})$

$F_e = 82.446*10^{-9}N$

Therefore

$\frac{F_e}{F_g} = 2.270*10^{39}$

We can here prove that the statement is True

7 0

3 years ago

Prove that f=ma where the symbols have their usual meaning.

jekas [21]

Explanation:

According to Newton's second law of motion:

Force is directly proportional to

Change of momentum/time taken

Change of momentum= mv-mu

where m is mass, u is initial velocity and v is final velocity. so,

F∝mv-mu/t

F∝m(v-u)/t

F∝ma (a=v-u/t)

F=kma where k is a constant

In SI units the value of k will become one so the equation will be:

F=ma

7 0

3 years ago

A grain barge travels on a river from point a to point b loading and unloading grain. the barge travels at a rate of 99 mph rela

NARA [144]

The distance from point a and point is equal for travels going back and forth. They would just differ in time and speed because of the sea's speed that propels the vessel. The solutions as as follows:

Distance upstream = Distance downstream
99(t + 2) = (99 + 1)(t)

Solving for t,
t = 198 hours

That means that the distance is equal to:
Distance = 99 miles/hour * (198 + 2 hours)
Distance = 19,800 miles

6 0

4 years ago