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Natalija [7]
3 years ago
12

The number a point corresponds to on a number line is called it's

Mathematics
1 answer:
cestrela7 [59]3 years ago
8 0
It's called a coordinate
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What is the inverse of the following statement? If m is the midpoint of PQ, then PM is congruent to QM
stepan [7]

The inverse of the statement is M be the point on PQ since PM is congruent to QM than M is midpoint on the PQ.

<h3>What do you mean by inverse?</h3>

Inverse of the statement means that explain the condition in reverse way or vice versa.

Since, M is the midpoint of PQ, then PM is congruent to QM.
Proving in reverse way, let m be the point between P and Q the distance M from P is equal to the distance from M to Q. Which implies that M lies as the mid of the P and Q.

Thus, the inverse of the statement is M be the point on PQ since PM is congruent to QM than M is midpoint on the PQ.

Learn more about inverse here:
brainly.com/question/5338106


#SPJ1

5 0
2 years ago
The number of lines that can be drawn perpendicular to a given line at a given point on that line in a plane is
Neko [114]
Only one.
it has a long proof.
3 0
3 years ago
Read 2 more answers
Jenny can type 1,200 words in just 15 minutes. How many words can she types in anhour?
seropon [69]
She can type 4,800 words in one hour.
7 0
3 years ago
Amir stands on a balcony and throws a ball to his dog, who is at ground level. The ball's height (in meters above the ground), x
kumpel [21]

Answer:

12m

Step-by-step explanation

If the height of the ball after x seconds be modelled by the equation

h(x)=−(x−2)² +16

The height of the ball at the time it is thrown will be the height at the initial time. At that point that it is initially thrown the time is 0seconds i.e x = 0

To get the height at t x = 0seconds, we will substitute x = 0 into the modeled function to have;

h(0) = -(-0-2)²+16.

h(0) = -(-2)²+16

h(0) = -4+16

h(0) = 12

The height of the ball at the time the ball is thrown is 12m

4 0
4 years ago
Read 2 more answers
Answer like gauss 1+3+5+7+...=999
raketka [301]

1+3+5+7+...+999 =

= 1+2+3+4+...+500

     +1+2+3+...+499

= 2·(1+2+3+...+499) + 500

= 2·(499·500)/2 + 500

= 499·500 + 500

= 500·(499 + 1)

= 500·500

= 250.000

7 0
3 years ago
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