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riadik2000 [5.3K]

2 years ago

10

Help me again? This is my test

1 answer:

HACTEHA [7]2 years ago

3 0

Answer:

Estimate: 7

Actual: 6.63 (>)

Step-by-step explanation:

I hope this helps you out with your question! Can you plz consider marking me brainliest and thanks! Plz tell me how the answer was! It feel nice to be appreciated! Comment /free for a giveaway entry of 20 thanks and 2 brainliest. Have an awesome day! Let me know if you have any questions!

-KaraYeaton18

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The tip added should reduce the meal subtotal by 18 %

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3 years ago

find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.

DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

Or, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}$

Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × $\frac{171}{4}$

∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

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3 years ago