Answer:
Y=(-x/2)-3
Step-by-step explanation:
You have two points:
(0,-3) and (-4,-1)
The formula of line trough two points is:
(Y-y1)/(y2-y1)=(x-x1)/(x2-x1)
So put these two point like (x1,y1) and (x2,y2) you will get
(Y+3)/(-1+3)=(x-0)/(-4-0)
Y+3=2x/(-4)
Y=-x/2-3
Graph the line using the slope and y-intercept, or two points.
Slope:
1
2
1
2
y-intercept:
(
0
,
−
2
)
(
0
,
-
2
)
x
y
0
−
2
2
−
1
Answer:
The midpoint of a line segment joining (a, b) and (c,d) is given by the formula
Step-by-step explanation:
If point <em>M </em>in the figure lies midway between points and , point <em>M</em> is called the midpoint of segment. To find the coordinates of <em>M</em>, we average the x-coordinates and average the y-coordinates of P and Q.
So the the midpoint of the line segment with endpoints at (a,b) and (c,d) is the point with coordinates of
I believe it would be -16k^3 + 3v^4 - 9k^3 + 6v^4