A sample of oxygen gas had a volume of 2.50 L at STP.
Answer:
The solution to the given problem is done below.
Explanation:
a)
i) =( 0.002 μg / L )( 1mg / 1000 μg )( 1L / kg )( 1000 mil / 1 billion) = 0.002 ppb
ii) =( 0.002 μg / L )( 1mg / 1000 μg )( 1L / kg )( 1,000,000 mil / 1 trillion) = 2 ppt
iii) =( 0.002 μg / L )( 1 mole / 540g ) = 3.7 x
μM.
b)
i) =( 0.002 μg / g ) = 0.002 ppm
ii) In solids, ppb = μg/kg
=( 0.002 μg / g )( 1000 mil/ 1 billion) = 2 ppb
Answer:
Not sure about this one, sorry
Explanation:
In balancing chemical equations, all you need to do is make it so that you have the same number of each element on both sides of the eqtn (if I have 5C on the left, I have to have 5C on the right — an element can’t magically appear or disappear); that being said:
(2)C2H6 + 7O2 ➡️ 6H2O + 4CO2
(12)HClO4 + P4O10 ➡️ 4H3PO4 + (6)Cl2O7
2N2 + (5)O2 + 2H2O ➡️ 4HNO3
(3)CaCl2 + 2Na3PO4 ➡️ (1)Ca3(PO4)2 + 6NaCl
4FeS + 7O2 ➡️ 2Fe2O3 + 4SO2
Ca= Calcium, and (CO3) = Chloride. Ca(CO3) is Calcium Chloride!