1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rewona [7]
3 years ago
14

What could two atoms of the same element form?

Chemistry
2 answers:
scZoUnD [109]3 years ago
8 0
Covalent bonds but not ionic 
weeeeeb [17]3 years ago
5 0
It will form a Covalent bond
You might be interested in
Materials
nikitadnepr [17]

Answer:

Limestone caves are formed when acid rain occurs.

Explanation:

When chalk pieces which is made of calcium carbonate react with acetic acid, it produces carbon dioxide, calcium acetate, and water. When calcium carbonate react with Carbonated Water produces calcium bicarbonate. Limestone cave forms when the dissolution of limestone occur when rainwater which is acidic due to the addition of carbondioxide in the air react with limestone. This dissolution removes the lime from the rock and caves are formed.

8 0
3 years ago
Hydrazine (N2H4) is a fuel used by some spacecraft. It is normally oxidized by N2O4 according to the following equation: N2H4(l)
vitfil [10]

Answer:

The enthalpy of the reaction is coming out to be -380.16 kJ.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

N_2H_4(l)+N_2O_4(g)\rightarrow 2N_2O(g)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2 mol\times \Delta H_f_{(N_2O)})+(2 mol\times\Delta H_f_{(H_2O)} )]-[(1 mol\times \Delta H_f_{(N_2H_4)})+(1 mol\times \Delta H_f_{(N_2O_4)})]

We are given:

\Delta H_f_{(N_2O)}=81.6 kJ/mol\\\Delta H_f_{(H_2O)}=-241.8 kJ/mol\\\Delta H_f_{(N_2H_4)}= 50.6 kJ/mol\\\Delta H_f_{(N_2O_4)}=9.16 kJ/mo

Putting values in above equation, we get:

\Delta H_{rxn}=[(2 mol\times 81.6 kJ/mol)+2 mol\times -241.8 kJ/mol)]-[(1 mol\times (50.6 kJ/mol))+(1 mol\times (9.16))]\\\\\Delta H_{rxn}=-380.16 kJ

Hence, the enthalpy of the reaction is coming out to be -380.16 kJ.

6 0
3 years ago
An ionic compound has a very negative heat of solution in water. Would you expect it to be soluble or insoluble in water?.
ddd [48]

Answer:

It will be Insolube in water

8 0
2 years ago
Determine the [OH−] of a solution that is 0.115 M in CO32−. For carbonic acid (H2CO3), Ka1=4.3×10−7 and Ka2=5.6×10−11.
lianna [129]

Answer:

[OH⁻] = 4.3 x 10⁻¹¹M in OH⁻ ions.

Explanation:

Assuming the source of the carbonate ion is from a Group IA carbonate salt (e.g.; Na₂CO₃), then 0.115M Na₂CO₃(aq) => 2(0.115)M Na⁺(aq) + 0.115M CO₃²⁻(aq). The 0.115M CO₃²⁻ then reacts with water to give 0.115M carbonic acid; H₂CO₃(aq) in equilibrium with H⁺(aq) and HCO₃⁻(aq) as the 1st ionization step.

Analysis:

            H₂CO₃(aq)     ⇄     H⁺(aq)    +    HCO₃⁻(aq); Ka(1) = 4.3 x 10⁻⁷

C(i)          0.115M                      0                  0

ΔC              -x                        +x                  +x

C(eq)    0.115M - x                   x                    x

            ≅ 0.115M

Ka(1) = [H⁺(aq)][HCO₃⁻(aq)]/[H₂CO₃(aq)] = [(x)(x)/(0.115)]M = [x²/0.115]M

= 4.3 x 10⁻⁷  => x = [H⁺(aq)]₁ = SqrRt(4.3 x 10⁻⁷ · 0.115)M = 2.32 x 10⁻⁴M in H⁺ ions.

In general, it is assumed that all of the hydronium ion comes from the 1st ionization step as adding 10⁻¹¹ to 10⁻⁷ would be an insignificant change in H⁺ ion concentration. Therefore, using 2.32 x 10⁻⁴M in H⁺ ion  concentration, the hydroxide ion concentration is then calculated from

[H⁺][OH⁻] = Kw => [OH⁻] = (1 x 10⁻¹⁴/2.32 x 10⁻⁴)M = 4.3 x 10⁻¹¹M in OH⁻ ions.

________________________________________________________

NOTE: The 2.32 x 10⁻⁴M  value for [H⁺] is reasonable for carbonic acid solution with pH ≅ 3.5 - 4.0.

4 0
3 years ago
What is the difference between water and alcohol
Rudik [331]

Answer:

water is H2O having different structure than alcohol R-OH which means they have different properties too.

Explanation:

In water one oxygen atom  is covalently bound with  two hydrogen atoms while alcohol is an organic compound  having Oh group attached to the carbon chain.

Other than liquid water can occur in solid form that is ice and in gaseous form that is vapors too while alcohol only present in liquid form.

heat of evaporation of alcohol is lower than water means water need more heat to evaporate than alcohol that is why we can say alcohol having more cooling effect than water.

7 0
2 years ago
Other questions:
  • A mineral sample is obtained from a region of the country that has high arsenic contamination. An elemental analysis yields the
    8·1 answer
  • Naoh is a strong electrolyte, and ch3oh is a nonelectrolyte. how is the solution of naoh different from that of ch3oh?
    12·1 answer
  • Which of the following does not participate in, nor is a component of, the electron transport chain? (Remember that molecules ca
    8·1 answer
  • What is the energy of an electromagnetic wave that has a wavelength of 0.035 m?
    7·1 answer
  • What is the electron configuration using core notation for Ca2+?
    14·1 answer
  • What is the pH of a solution that has a [OH-] 2.65*10 -9 M
    11·1 answer
  • Which of the following substances act as a catalyst in the body?
    5·2 answers
  • Which statements describe turbidity? Check all that apply. Turbidity is a measure of water clarity. Turbidity may be caused by s
    6·1 answer
  • A certain first-order reaction a → b is 25% complete in 42 min at 25°c. What is the half-life of the reaction?.
    6·1 answer
  • Please help! Is there another way that 3.40x10^-19J can be imputed on a computer. I have the right answer but it is wrong.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!