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3 years ago

Choose the incorrect answer below concerning absolute zero.

2 answers:

8 0

Is equal to 0 k .This is because an absolute zero temperature is the temperature in which nothing can be cooled. The standard measurment for temperature is celcius which is already 0 but when we are converting 0 K to celcius we will gwt 273 celcius which is definitely not an absolute zero

Alisiya [41]3 years ago

7 0

Answer: Option (c) is the correct answer.

Explanation:

Absolute zero is defined as the lowest temperature at which motion of particles is the least and heat would be minimal.

Absolute temperature is represented as zero kelvin and it is also equivalent to $-273.15^{o}C$ .

For example, an hour old cup of a tea is actually colder than fire over a stove but hotter than an ice cube.

Therefore, we can conclude that the incorrect answer below concerning absolute zero is that it is equal to $0^{o}C$ .

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Type the correct answer in each box.

krok68 [10]

Answer:

2KI → 2K + I₂

Explanation:

(not my definition, but form a trustworthy source)

The definition of a decomposition reaction is:

a chemical reaction in which one reactant breaks down into two or more products.

In this case, potassium iodide will decompose into potassium and iodine.

2KI → 2K + 2I

2 Potassium and 2 Iodine on both sides, so equation is balanced.

Or, it can be written as 2KI → 2K + I₂

8 0

2 years ago

A greenhouse is filled with air that cotains more carbon dixoide than normal air has. How might phothsyphness and plant growth b

vekshin1

Answer:

See explanation

Explanation:

We know that photosynthesis involves the combination of carbon dioxide and water in the presence of sunlight to yield glucose.

If the atmosphere is rich in carbon dioxide such as in a green house where air is filled with carbon dioxide, the rate of photosynthesis is increased.

As the rate of photosynthesis is increased, the growth of plants is also increased.

Hence, in a greenhouse where the air contains more carbon dioxide, the rate of plant growth increases.

4 0

3 years ago

What happens to the reaction rate as a reactant gets used up?

Oxana [17]

Answer: B. The rate goes down

Explanation:

8 0

3 years ago

Pls helppp

defon

The heat absorbed to raise temperature : Q = 31350 J

<h3>Further explanation </h3>

Given

m = mass = 150 g

Δt = Temperature difference : 50 °C

Required

Heat absorbed

Solution

Heat can be formulated

The specific heat of water = c = 4.18 J/g °C

Input the value :

Q = 150 x 4.18 x 50

Q = 31350 J

6 0

3 years ago

In Part III, the phenolphthalein indicator is used to monitor the equilibrium shifts of the ammonia/ammonium ion system. The phe

AnnZ [28]

The pink color in the solution fades. Some of the colored indicator ion converts to the colorless indicator molecule.

<h3>Explanation</h3>

What's the initial color of the solution?

$\text{NH}_4\text{Cl}$ is a salt soluble in water. $\text{NH}_4\text{Cl}$ dissociates into ions completely when dissolved.

$\text{NH}_4\text{Cl} \; (aq)\to {\text{NH}_4}^{+} \; (aq) +{\text{Cl}}^{-} \; (aq)$ .

The first test tube used to contain $\text{NH}_4\text{OH}$ . $\text{NH}_4\text{OH}$ is a weak base that dissociates partially in water.

$\text{NH}_4\text{OH} \; (aq) \rightleftharpoons {\text{NH}_4}^{+} \;(aq)+ {\text{OH}}^{-} \; (aq)$ .

There's also an equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$ .

$\text{OH}^{-}$ ions from $\text{NH}_4\text{OH}$ will shift the equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ to the right and reduce the amount of ${\text{H}_3\text{O}}^{+}$ in the solution.

The indicator equilibrium will shift to the right to produce more ${\text{H}_3\text{O}}^{+}$ ions along with the colored indicator ions. The solution will show a pink color.

What's the color of the solution after adding NH₄Cl?

Adding $\text{NH}_4\text{Cl}$ will add to the concentration of ${\text{NH}_4}^{+}$ ions in the solution. Some of the ${\text{NH}_4}^{+}$ ions will combine with $\text{OH}^{-}$ ions to produce $\text{NH}_4\text{OH}$ .

The equilibrium between $\text{OH}^{-}$ and ${\text{H}_3\text{O}}^{+}$ ions will shift to the left to produce more of both ions.

${\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)$

The indicator equilibrium will shift to the left as the concentration of ${\text{H}_3\text{O}}^{+}$ increases. There will be less colored ions and more colorless molecules in the test tube. The pink color will fade.

7 0

4 years ago