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2 years ago

Look at the two containers of water and their starting conditions shown above.

Chemistry

2 answers:

Shkiper50 [21]2 years ago

6 0

the answer is D because if an equal amount of heat is absorbed by the water in the containers, both water temperatures will increase, but Container B's will increase more.

When heat is absorbed by a substance, the substance's temperature increases. The amount that the temperature increases depends on the volume of the substance—the greater the volume, the less the temperature increases.

The water in Containers A and B has the same temperature, but Container A's water has a greater volume. If an equal amount of heat is added to both containers, Container A's water temperature will not increase as much as Container B's.

Umnica [9.8K]2 years ago

3 0

THE ANSWER IS

D;Both water temperatures will increase, but Container B's will increase more.

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What is the percent nitrogen in NaN*O_{3} ?

Naily [24]

I am not 100% this is right but

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1 year ago

The compound NaCl (salt) has the same properties as sodium (Na) and chlorine (CI) because it is made of both of those elements.

grin007 [14]

Answer:

False.

Explanation:

Hello.

In this case since sodium is a soft brilliant metal and chlorine is a green gas at normal conditions, they have totally different properties. Thus, since sodium chloride is also known as the table salt which is present as white crystals we can infer that the compound does not have the same properties, therefore it is false.

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2 years ago

How many electrons are transferred during the formation of one molecule of al2o3?

lukranit [14]

Answer:
Six electrons are transferred in the formation of Al₂O₃.

Explanation:
Aluminium metal and Oxygen react to form Al₂O₃ as,

2 Al + 3/2 O₂ → Al₂O₃

Oxidation number of Al on left hand side is zero, while than on right hand side in Al₂O₃ is +3. Means it has lost 3 electrons per one atom and six electrons per two atoms. Also, the oxidation number of O at left hand side in O₂ is zero, while that in Al₂O₃ it is -2 per atom and -6 per 3 atoms.

So, two Al atoms have lost 6 electrons and 3 O atoms have gained six electrons.

4 0

3 years ago

H2(g) + Br2(l) ⇄ 2HBr(g) Kc = 4.8 × 108

elena-14-01-66 [18.8K]

Answer:

1.5 × 10⁻⁹M

Explanation:

1. Equilibrium equation

H₂(g) + Br₂(l) ⇄ 2HBr(g)

2. Equilibrium constant

The liquid substances do not appear in the expression of the equilibrium constant.

$k_c=\dfrac{[HBr(g)]^2}{[H_2]}=4.8\times 10^8M$

3. ICE table.

Write the initial, change, equilibrium table:

Molar concentrations:

H₂(g) + Br₂(l) ⇄ 2HBr(g)

I 0.400 0

C - x +2x

E 0.400 - x 2x

4. Substitute into the expression of the equilibrium constant

$4.8\times 10^8=\dfrac{(2x)^2}{0.400-x}$

5. Solve the quadratic equation

192,000,000 - 480,000,000x = 4x²

x² + 120,000,000x - 48,000,000 = 0

Use the quadratic formula:

$x=\dfrac{-120,000,00\pm\sqrt{(120,000,000)^2-4(1)(-48,000,000}}{2(1)}$

The only valid solution is x = 0.39999999851M

Thus, the final concentration of H₂(g) is 0.400 - 0.39999999851 ≈ 0.00000000149 ≈ 1.5 × 10⁻⁹M

8 0

3 years ago

How many moles of carbon dioxide will be produced from the complete combustion of 13.6 moles of butane?

Aleks04 [339]

Answer:

54.4 mol

Explanation:

the equation for complete combustion of butane is

2C₄H₁₀ + 13O₂ ---> 8CO₂ + 10H₂O

molar ratio of butane to CO₂ is 2:8

this means that for every 2 mol of butane that reacts with excess oxygen, 8 mol of CO₂ is produced

when 2 mol of C₄H₁₀ reacts - 8 mol of CO₂ is produced

therefore when 13.6 mol of C₄H₁₀ reacts - 8/2 x 13.6 mol = 54.4 mol of CO₂ is produced

therefore 54.4 mol of CO₂ is produced

5 0

2 years ago