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Dimas [21]
3 years ago
13

2.71, 2 3/4, square root of 5, 5/2 least to greatest

Mathematics
2 answers:
STALIN [3.7K]3 years ago
6 0
Order from <span> least to greatest
</span> 
square root of 5, 5/2, 2.71, 2 3/4

hope it helps
Lapatulllka [165]3 years ago
5 0
2.71
2 3/4 = 2.75
sqrt 5 = 2.24
5/2 = 2.5

least to greatest : sqrt 5, 5/2, 2.71, 2 3/4
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What is w equal to?

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Answer:

If you actually meant f(x)=2x+3x−1 ,

then note it can be rewritten as:

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y−2=5x−1⟹1y−2=x−15

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The fracture strength of tempered glass averages 14 (measured in thousands of pounds per square inch) and has standard deviation
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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The fracture strength of tempered glass averages 14 (measured in thousands of pounds per square inch) and has standard deviation 2.

This means that \mu = 14, \sigma = 2

Sample of 100:

This means that n = 100, s = \frac{2}{\sqrt{100}} = 0.2

What is the probability that the average fracture strength of 100 randomly selected pieces of this glass exceeds 14.2?

This is 1 subtracted by the p-value of Z when X = 14.2. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

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Z = 1 has a p-value of 0.8413.

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