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lesya [120]
2 years ago
6

Answer please easy question​

Mathematics
2 answers:
garri49 [273]2 years ago
8 0

Answer: The answer is x=512

(I did it on paper)

borishaifa [10]2 years ago
4 0

8 = \sqrt[3]{x}

Cube both sides

512 = x

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Match the fractions that are equivalent to each other?
MrRissso [65]

Answer:

1&a 2&b 3&c 4&d

Step-by-step explanation:

...

4 0
3 years ago
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-2x(6x^4 -7x^2 +x-5 in standard form pls
LuckyWell [14K]

Answer:

-12x^5 + 14x^3 -2x^2 + 10x

Step-by-step explanation:

-2x(6x^4 -7x^2 +x-5) =

-12x^5 + 14x^3 -2x^2 + 10x

8 0
3 years ago
The graph of a bicycle ramp contains the points (-6,0) and (3,3). What is the slope of the ramp?
olasank [31]
The slope of the ramp would be 5/9
7 0
2 years ago
If the farmer has 250 feet of fencing to create a rectangular pen, define a function f that expresses the area of the field (mea
hoa [83]

Answer:

Maximum area possible

f(max)  = 3906,25 ft²

Dimensions:

a  = 62,5  ft

w  = 62,5 ft

Step-by-step explanation:

Perimeter of the rectangular fencing    P  =  250 feet

And sides of the rectangle  a  and  w (width of rectangle)

Then

A =  a*w

2a  + 2w  = 250       ⇒  a  =  (250 -2w)/ 2    ⇒  a = 125 - w

f(w)  =  (125  - w ) *w        f(w)  = 125w - w²  

Taking derivatives both sides of the equation

f´(w)   =  125  - 2w              f´(w)   = 0           125  - 2w = 0

w = 125/2

w = 62,5 ft            ⇒  a = 125 - 62,5

a = 62,5 ft

f(max)  = ( 62,5)²

f(max)  = 3906,25 ft²

8 0
3 years ago
In a study of the progeny of rabbits, Fibonacci (ca. 1170-ca. 1240) encountered the sequence now bearing his name. The sequence
expeople1 [14]

The question in part c is not clear, nevertheless, part a and part b would be solved.

Answer:

a. The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

b. The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

Step-by-step explanation:

a. Given

an + 2 = an + an + 1

where a1 = 1 and a2 = 1.

a3 = a1 + a2

= 2

a4 = a2 + a3

= 3

a5 = a3 + a4

= 5

a6 = a5 + a4

= 8

a7 = a6 + a5

= 13

a8 = a7 + a6

= 21

a9 = a8 + a7

= 34

a10 = a9 + a8

= 55

a11 = a10 + a9

= 89

a12 = a11 + a10

= 144

The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

(b)

Given

bn = an+1/an

b1 = a2/a1

= 1/1 = 1.000

b2 = a3/a2

= 2/1 = 1.000

b3 = a4/a3

= 3/2 = 1.500

b4 = a5/a4

= 5/3 = 1.667

b5 = a6/a5

= 8/5 = 1.600

b6 = a7/a6

= 13/8 = 1.625

b7 = a8/a7

= 21/13 = 1.615

b8 = a9/a8

= 34/21 = 1.619

b9 = a10/a9

= 55/34 = 1.618

b10 = a11/a10

= 89/55 = 1.618

The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

6 0
2 years ago
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