A bag is dropped from a hovering helicopter. After 42.4s, calculate the bag’s displacement.

Physics

1 answer:

Ann [662]3 years ago

3 0

Answer:

8,809.024m

Explanation:

Displacement , y = (gt^2/2 )

g = 9.8 m/s^2

t = 42.4s

y = (9.8 (42.4*42.4)) / 2

y = 8,809.024m

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Four identical particles of mass 0.514 kg each are placed at the vertices of a 4.70 m x 4.70 m square and held there by four mas

Alona [7]

In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.

Our values are given by:

m = 0.514kg

I = 4.7m (each side)

A) For the case when the axis passes through the midpoints of opposite sidesand lies in the plane of the square. The formula is given by,

$I = 4m (\frac{l}{2})^2\\I = 4*(0.514)(\frac{4.7}{2})^2\\I = 11.35kgm^2\\$

B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,

$I = 2m(\frac{l}{2})^2+2m(\frac{l}{2}^2+l^2)\\I = 2*(0.514)*(\frac{4.7}{2})^2+2*(0.514)*((\frac{4.7}{2})^2+4.7^2)\\I = 34.06Kgm^2$