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Sholpan [36]
3 years ago
10

A bag is dropped from a hovering helicopter. After 42.4s, calculate the bag’s displacement.

Physics
1 answer:
Ann [662]3 years ago
3 0

Answer:

8,809.024m

Explanation:

Displacement , y = (gt^2/2 )

g = 9.8 m/s^2

t = 42.4s

y = (9.8 (42.4*42.4)) / 2

y = 8,809.024m

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In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.

Our values are given by:

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B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,

I = 2m(\frac{l}{2})^2+2m(\frac{l}{2}^2+l^2)\\I = 2*(0.514)*(\frac{4.7}{2})^2+2*(0.514)*((\frac{4.7}{2})^2+4.7^2)\\I = 34.06Kgm^2

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I = \frac{1}{2}*l^2

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I = 11.045kgm^2

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