Answer:
0.12
Explanation:
The acceleration due to gravity of a planet with mass M and radius R is given as:
g = (G*M) / R²
Where G is gravitational constant.
The mass of the planet M = 3 times the mass of earth = 3 * 5.972 * 10^24 kg
The radius of the planet R = 5 times the radius of earth = 5 * 6.371 * 10^6 m
Therefore:
g(planet) = (6.67 * 10^(-11) * 3 * 5.972 * 10^24) / (5 * 6.371 * 10^6)²
g(planet) = 1.18 m/s²
Therefore ratio of acceleration due to gravity on the surface of the planet, g(planet) to acceleration due to gravity on the surface of the planet, g(earth) is:
g(planet)/g(earth) = 1.18/9.8 = 0.12
Answer:
A. 12,240.
Explanation:
1,530 times 8.0 = 12,240.
hope this helped :)
While riding in a hot air balloon,
which is steadily at a speed of 1.01 m/s, and your phone accidentally falls.
<span>(a)
</span>The
speed of your phone after 4 s is:
V= u +
at
V= 1.01
+ (9.8)(4)
V=
40.21 m/s
<span>(b)
</span>The balloon
is ____ far:
V = u +
at
V= 1.01
+ (9.8)(1)
V=10.81
–distance at 1 one second
V= u +
at
V= 1.01
+ (9.8)(2)
V= 20.61-distance
at 2 seconds
V= u+ at
V=
30.41- distance at 3 seconds
V=
40.21- distance at 4 seconds
D=
102.04 m
<span>(c)
</span>If the
balloon is rising steadily at 1.01 m/s:
V= -1.1
m/s
<span> </span>
Answer:
Explanation:
3.4 = 18.87x + 23.97
collecting like terms
3.4 - 23.97 = 18.87x
-20.57 = 18.87x
dividing both sides by 18.87
x = -20.57/18.87
x= -1.09
Answer:
The magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.
Explanation:
Given;
distance half way between the parallel wires, r = ¹/₂ (40 cm) = 20 cm = 0.2 m
current carried in opposite direction, I₁ and I₂ = 10 A and 20 A respectively
The magnitude of the magnetic field halfway between the wires can be calculated as;
where;
B is magnitude of the magnetic field halfway between the wires
I₁ is current in the first wire
I₂ is current the second wire
μ₀ is permeability of free space
r is distance half way between the wires
Therefore, the magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.
