I think the answer its false i dont know how to explain that but it is false that what my teacher told me
The image height is -10 cm (the image is upside down)
Explanation:
We can solve the problem by using the mirror equation:

where:
f = 5 cm is the focal length of the mirror
p = 10 cm is the distance of the object from the mirror
q is the distance of the image from the mirror
Solving for q, we find:

So, the distance of the image from the mirror is 10 cm.
Now we can find the image height by using the magnification equation:

where
y' is the height of the image
y = 1 cm is the height of the object
and using
p = 10 cm
q = 10 cm
We find the size of the image:

where the negative sign indicates that the image is upside down.
#LearnwithBrainly
The wavelength of the third line in the Lyman series, and identify the type of EM radiation
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.
1 / lambda = R(h)* (
-
)
= 109678 (
-
)
= 109678 (8/9)
Lambda = 9 / (109678 * 8 )
= 102.6 *
m = 102.6 nm
To learn more about Lyman series here
brainly.com/question/5762197
#SPJ4
Answer:
W = 8.01 × 10^(-17) [J]
Explanation:
To solve this problem we need to know the electron is a subatomic particle with a negative elementary electrical charge (-1,602 × 10-19 C), The expression to calculate the work is given by:
W = q*V
where:
q = charge = 1,602 × 10^(-19) [C]
V = voltage = 500 [V]
W = work [J]
W = 1,602 × 10^(-19) * 500
W = 8.01 × 10^(-17) [J]