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3 years ago

Needing help with this equationx/2-5=3

Mathematics

2 answers:

Readme [11.4K]3 years ago

7 0

The correct answer is x= -9

steps:
x/2-5=3
x/-3=3
multiply both sides by -3
x=-9

cestrela7 [59]3 years ago

3 0

Answer:

x=16

Step-by-step explanation:

x/2-5=3

x/2-5=3+5=

x/2=8

x/2=8×2

x=16

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Step-by-step explanation:

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3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

kompoz [17]

$f_{X,Y,Z}(x,y,z)=\begin{cases}Ce^{-(0.5x+0.2y+0.1z)}&\text{for }x\ge0,y\ge0,z\ge0\\0&\text{otherwise}\end{cases}$

is a proper joint density function if, over its support, $f$ is non-negative and the integral of $f$ is 1. The first condition is easily met as long as $C\ge0$ . To meet the second condition, we require

$\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}$

b. Find the marginal joint density of $X$ and $Y$ by integrating the joint density with respect to $z$ :

$f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz$

$\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}$

Then

$\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy$

$\approx\boxed{0.12886}$

c. This probability can be found by simply integrating the joint density:

$\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz$

$\approx\boxed{0.012262}$

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3 years ago

You went shopping for classroom supplies. You bought 255 blue pens, 100 red pens, and 189 green pens. How many pens did you buy

jeyben [28]

I bought 544 pens in all

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3 years ago

What are the dimensions of a rectangle with an area of 12 square cm and a perimeter of 14 cm?

kow [346]

Answer:

For the rectangle

Length=ℓ

Breadth=b

Area is 12 cm2

ℓb=12

Perimeter is 16 cm

2(ℓ+b)=16

ℓ+b=8

Substitute b=12ℓ from first equation

ℓ+12ℓ=8

ℓ2+12=8ℓ

ℓ2−8ℓ+12=0

Use quadratic formula (x=−b±√b2−4ac2a) to find ℓ

ℓ=−(−8)±√(−8)2−(4×1×12)2×1

ℓ=8±√162

ℓ=8±42

ℓ1=8+42=6

ℓ2=8−42

Step-by-step explanation:

For the rectangle

Length=ℓ

Breadth=b

Area is 12 cm2

ℓb=12

Perimeter is 16 cm

2(ℓ+b)=16

ℓ+b=8

Substitute b=12ℓ from first equation

ℓ+12ℓ=8

ℓ2+12=8ℓ

ℓ2−8ℓ+12=0

Use quadratic formula (x=−b±√b2−4ac2a) to find ℓ

ℓ=−(−8)±√(−8)2−(4×1×12)2×1

ℓ=8±√162

ℓ=8±42

ℓ1=8+42=6

ℓ2=8−42

5 0

3 years ago

Read 2 more answers

Needing help with this equationx/2-5=3​

Needing help with this equationx/2-5=3