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2 years ago

How many solutions does the equation have?

2 answers:

7 0

$2(2x+5)=4(x+3)\\2\times2x+2\times5=4\times x+4\times3\\4x+10=4x+12\ \ \ \ |subtract\ 4x\ from\ both\ sides\\10=12-FALSE\\\\therefore,\ answer\ is\ \boxed{C.\ No\ solution}$

kondor19780726 [428]2 years ago

4 0

When you distribute the problem become
4x+10=4x+12
Which is not possible. So your answer is no solution.
Hope that helps!

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Find the value of each variable

mylen [45]

Answer:

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2 years ago

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solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. x-2y+

Alekssandra [29.7K]

Answer:

x = -5, y = -6, z = -3

Step-by-step explanation:

Given the system of three equations:

$\left\{\begin{array}{l}x-2y+3z=-2\\6x+2y+2z=-48\\x+4y+3z=-38\end{array}\right.$

Write the augmented matrix for the system of equations

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)$

Find the reduced row-echelon form of the augmented matrix for the system of equations:

$\left(\begin{array}{ccccc}1&-2&3&|&-2\\6&2&2&|&-48\\1&4&3&|&-38\end{array}\right)\sim \left(\begin{array}{ccccc}1&-2&3&|&-2\\0&-14&16&|&36\\0&-6&0&|&36\end{array}\right)\sim \left(\begin{array}{ccccc}1&3&-2&|&-2\\0&16&-14&|&36\\0&0&-6&|&36\end{array}\right)$

Thus, the system of three equations is

$\left\{\begin{array}{r}x+3z-2y=-2\\16z-14y=36\\-6y=36\end{array}\right.$

From the last equation:

$y=-6$

Substitute it into the second equation:

$16z-14\cdot (-6)=36\\ \\16z=36-84\\ \\16z=-48\\ \\z=-3$

Substitute y = -6 and z = -3 into the first equation:

$x+3\cdot (-3)-2\cdot (-6)=-2\\ \\x=-2+9-12\\ \\x=-5$

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3 years ago

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kow [346]

Answer: x(x−6)

Step-by-step explanation:

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2 years ago

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Alchen [17]

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3 years ago

A rectangular swimming pool is 15 meters long, 10/1/2 meters wide and 2/1/2 meters deep.What is its volume

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8 0

2 years ago

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