Graph the image of the given triangle after the transformation with the rule (x, y)→(x−6, y−4) .
1 answer:
Answer: See the figure attached.
Step-by-step explanation:
Observe the figure attached. The vertices of the triangle ABC have the following coordinates:
A(2,5); B(6,2) and C(3,-5)
To graph the image (in this case we can identify it as A'B'C'), you must use the rule →
.
Then, you have to subtract 6 units from the x-coordinate of each vertex and subtract 4 units from the y-coordinate of each vertex.
Therefore, you get:
Vertex A'→
Vertex B'→
Vertex C'→
Having the vertices of the image A'B'C', you can graph it (See the figure attached).
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Answer:
m =
Step-by-step explanation:
<h3>Finding the slope of the given line </h3>We need to find the slope of this equation to find the slope of a line perpendicular to it. This means we must solve for y.
Start off by subtracting 8x from both sides of the equation to start isolating the variable y.
Now solve for y by dividing both sides of the equation by -7.
This can be broken into two parts by distributing the negative sign from the -7 into the 9 and -8x like so:
The slope of a line is the coefficient of x, so in this case the slope of the given line () is
.
Two lines that are perpendicular would have opposite reciprocal slopes, which means the perpendicular slope would be the negative counterpart and would be flipped.
For example, if you have 2 as the slope of one of the perpendicular lines, the other line would be the opposite (-2) reciprocal ().
Therefore, since we have the slope of one of the perpendicular lines (the given line), we would find the opposite reciprocal of it's slope to solve this problem.
Slope:
- Opposite:
- Reciprocal:
The slope of the line perpendicular to is
.