Prove that sin²a + cos²a = 1 and =
le="\frac{1}{cos^{2}a }" alt="\frac{1}{cos^{2}a }" align="absmiddle" class="latex-formula"> + tan²a (a not alpha)
1 answer:
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Step-by-step explanation:
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The center of the circle is (h,k) = (-2,-3)
The radius of the circle is r = 2
The standard form of equation of the circle is
The general form of equation of the circle is
Here, (h,k) means centre of the circle.
r means radius of the circle.
given that coordinate points of centre of circle is (-2,-3).
Hence the (h,k) = (-2,-3)
<h3>How to find the radius of the circle?</h3>Now to find the radius of the circle
The distance from a circle's centre to its circumference is its radius.
The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.
using the formula, distance between the two points to obtain radius.
(h,k) = (-2,-3)
r = 2
subtitue the (h,k) and r values to get the standard form of equation of the circle.
Learn more about circle, refer:
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