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olga55 [171]
3 years ago
15

Prove that sin²a + cos²a = 1 and =

le="\frac{1}{cos^{2}a }" alt="\frac{1}{cos^{2}a }" align="absmiddle" class="latex-formula"> + tan²a (a not alpha)

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0

Answer:

\frac{1}{cos^2a }=  tan^2 a

Step-by-step explanation:

Explanation:-

Given   sin²a + cos²a = 1  

and

              \frac{1}{cos^{2} a}  \\= \frac{sin^2a+cos^2a}{cos^2a}  \\                         \\\\ = \frac{sin^2a}{cos^2a} +\frac{cos^2a}{cos^2a}

= tan²a + 1



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3 years ago
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Hello,
Nookie1986 [14]

Answer:

s = height above ground

s = 60 + 20 t - 4.9 t^2 (standard physics equation on earth)

at t = 0

s = 60 (clearly :)

now when does it hit the bleak earth?

That is when s = 0

4.9 t^2 - 20 t -60 = 0

solve quadratic and use the positive t (the negative t was back before you threw it if you had thrown it from the ground)

t = 6.09 or - 2.01

use t = 6.09

now to do the last part there are two obvious ways to get t at the peak

1. look for vertex of parabola

2. look for halfway between t = -2.01 and t = 6.09

I will do it the hard (11) waay by completing the square

4.9 t^2 - 20 t = -(s-60)

t^2 - 4.08 t = -.204 s + 12.2

t^2 - 4.08 t +2.04^2 = -.204 s +12.2 + 4.16

(t-2.04)^2 = -.204(s-80.2)

so

top at 80.2 meters at t = 2.04 s

===============

quick check on time

should be average of 6.09 and -2.01

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2 years ago
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Answer:

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Step-by-step explanation:

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good day, and be safe

∵∴∵∴∵∴∵∴∵      

⊕ΘΞΠΤ⊕      

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Question:

Find the gradient of the line passing through (6,8) and (4,10).

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-1 is the right answer.

Step-by-step explanation:

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