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olga55 [171]
3 years ago
15

Prove that sin²a + cos²a = 1 and =

le="\frac{1}{cos^{2}a }" alt="\frac{1}{cos^{2}a }" align="absmiddle" class="latex-formula"> + tan²a (a not alpha)

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0

Answer:

\frac{1}{cos^2a }=  tan^2 a

Step-by-step explanation:

Explanation:-

Given   sin²a + cos²a = 1  

and

              \frac{1}{cos^{2} a}  \\= \frac{sin^2a+cos^2a}{cos^2a}  \\                         \\\\ = \frac{sin^2a}{cos^2a} +\frac{cos^2a}{cos^2a}

= tan²a + 1



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Step-by-step explanation:

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Given the rectangle abcd shown below has a total area of 72. E is in the midpoint of bc and f is the midpoint of dc. What is the
scoray [572]

Refer to the attached image.

Given the rectangle ABCD of length 'l' and height 'h'.

Therefore, CD=AB = 'l' and BC = AD = 'h'

We have to determine the area of triangle AEF.

Area of triangle AEF = Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

Area of triangle ADF = \frac{1}{2}bh

= \frac{1}{2}(DF \times AD)

= \frac{1}{2}(\frac{l}{2} \times h)

=\frac{lh}{4}

Area of triangle ECF = \frac{1}{2}bh

= \frac{1}{2}(CF \times CE)

= \frac{1}{2}(\frac{l}{2} \times \frac{h}{2})

=\frac{lh}{8}

Area of triangle ABE = \frac{1}{2}bh

= \frac{1}{2}(AB \times BE)

= \frac{1}{2}(l \times \frac{h}{2})

=\frac{lh}{4}

Now, area of triangle AEF =

Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

= 72 - (\frac{lh}{4} + \frac{lh}{8} + \frac{lh}{4})

= 72 - (\frac{2lh+lh+2lh}{8})

=72 - (\frac{5lh}{8})

=72 - (\frac{5 \times 72}{8})

=\frac{72 \times 8 - (5 \times 72)}{8}

= 27 units

Therefore, the area of triangle AEF is 27 units.

8 0
3 years ago
1. Use the graph of the rational function
Mrrafil [7]

Answer:

As x \to -3^{+}, f(x) \to -\infty

Step-by-step explanation:

Given:

From the graph, we can conclude that:

The function has vertical asymptotes at x=-3\ and\ x=2

The function has horizontal asymptote at f(x)=0

Vertical asymptotes are those values of 'x' for which the functions tends towards infinity. Horizontal asymptote is the value of the function as the 'x' value tends to infinity.

Now, as x \to -3^{+} means the right hand limit of the function at x=-3

From the graph, the right hand limit is the right side of the asymptote of the function at x = -3. The right side shows that the function is tending towards negative infinity.

Therefore, As x \to -3^{+}, f(x) \to -\infty

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