Third length =
12-7 = 5
12+7 = 19
Third length can be only in this range
5Means the third length must be greater than 5 and less than 19.
Hope this helps!
Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°
To Find: The length of the park's boundary to the nearest yard.
Calculation:
The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc
or, (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)
or, (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 209.33 yards
or, (P) = 309.33 yards ≈309 yards
Hence, the option D:309 yards is the correct option.
3x9=27
21/3 = 7
so
7+27x9+5
27x9=243
243+7+5
answer is 255
To solve the inequality, you need to isolate/get the variable "p" by itself in the inequality:
5p + 26 < 72 Subtract 26 on both sides
5p + 26 - 26 < 72 - 26
5p < 46 Divide 5 on both sides to get "p" by itself
p < 9.2 Your answer is A
