All categories

4 years ago

You help me i'll help you.

Mathematics

2 answers:

Pepsi [2]4 years ago

5 0

Hi, I think the answer may be 2.
How I got my answer:
If x equals 18, divide 18 by 3 and you'll get 6, then divide 6 by the other 3 and your quotient should be 2.
Hope I helped!

kirza4 [7]4 years ago

3 0

X/3y has the value of 2. Here's the work x=18 so it's 18/3y and y=3 so you add the three in the place of y and multiply. 18/3(3) which gives you 18/9 and 18 divided by 9 is 2.

You might be interested in

What is the radius of a sphere with a surface area of 100TCm ?

tensa zangetsu [6.8K]

The radius is 5cm

Step-by-step explanation:

The surface area of a sphere is given by:

$SA = 4\pi r^2$

Here

Given

SA = 100π cm^2

Putting the values in the formula

$100\pi = 4\pi r^2\\r^2 = \frac{100\pi}{4\pi}\\r^2 = 25$

Taking square root on both sides

$\sqrt{r^2} = \sqrt{25}\\r = 5 cm$

The radius is 5cm

Keywords: Surface area, Radius

Learn more about surface area of sphere at:

#LearnwithBrainly

7 0

3 years ago

Rewrite the equation by completing the square x^2-4x=0

Dmitriy789 [7]

Answer:

(x+2)(x-2) = 0

Step-by-step explanation:

7 0

2 years ago

A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one

TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are $\binom44\binom{48}1=48$ possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by $\binom{13}1=13$ . So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

$\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024$

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing $\binom41\binom{48}4=778,320$ possible hands. Exactly 2 aces are drawn in $\binom42\binom{48}3=103,776$ hands. And so on. This gives a total of

$\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656$

possible hands containing at least 1 ace, and hence B occurs with probability

$\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412$

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. $P(A\cap B)=P(A)P(B)$ . This happens if

the hand has 4 aces and 1 non-ace, or
the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So $A\cap B$ consists of 96 possible hands, which occurs with probability