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pishuonlain [190]
4 years ago
6

You help me i'll help you.

Mathematics
2 answers:
Pepsi [2]4 years ago
5 0
Hi, I think the answer may be 2.
How I got my answer:
If x equals 18, divide 18 by 3 and you'll get 6, then divide 6 by the other 3 and your quotient should be 2.
Hope I helped!
kirza4 [7]4 years ago
3 0
X/3y has the value of 2. Here's the work x=18 so it's 18/3y and y=3 so you add the three in the place of y and multiply. 18/3(3) which gives you 18/9 and 18 divided by 9 is 2.
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Select the correct answer.
Eva8 [605]

Answer:

Equation C: 5/8x + 2..5 = 3/8x + 1.5 + 1/4x

Step-by-step explanation:

Let us go through each of the equations one by one.

Equation A: 2.3y+2+3.1y=4.3y+1.6+1.1y+0.4

This simplifies to

5.4y+2=5.4y+2

which has infinitely many solutions.

Equation B: 32x+25-21x=10x

this simplifies to

x+25=0

x=-25

which is exactly one solution.

Equation C: \frac{5}{8} x+2.5=\frac{3}{8}x+1.5+\frac{1}{4} x

this simplifies to

\frac{5}{8} x+2.5=\frac{5}{8} +1.5

2.5=1.5

There's no way this is going to be possible; this equation has no solutions.

Equation D: \frac{1}{3} x+\frac{1}{7} x=\frac{3}{7} x

this gives

\frac{1}{3} =\frac{2}{7} y

y=\frac{7}{6}

which is exactly one solution.

Thus we see that it is equation C that has no solutions.

3 0
4 years ago
Will award brainliest to correct answer!
Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

\angle \: ABP =  \frac{180 - 80}{2}  = 50 \degree

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)

6 0
3 years ago
HELP DUE AT 9:00 PM!
alina1380 [7]
A is 5,6 that is the answer for A gotta go but maybe someone else can help with the other ones
4 0
3 years ago
Read 2 more answers
At 6:00 A.M. the temperature was 33°F. By noon the temperature had increased by 10°F and by 3:00 P.M. it had increased another 1
daser333 [38]
The temperature must rise 5 degrees to reach the original temperature
6 0
3 years ago
Read 2 more answers
Determine the domain of the function (fog)(x) where f(x)=3x-1/x-4 and g(x)=x+1/x
Katarina [22]

Answer: (-∞,-1) ∪ (0,+∞)

Step-by-step explanation: The representation fog(x) is a representation of composite function, meaning one depends on the other.

In this case, fog(x) means:

fog(x) = f(g(x))

fog(x) = 3(x+\frac{1}{x} )-\frac{1}{x+\frac{1}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{1}{\frac{x^{2}+x}{x} } -4

fog(x)=3x+\frac{3}{x} -\frac{x}{x^{2}+x} -4

fog(x)=\frac{3x^{2}(x^{2}+x)+3(x^{2}+x)-x-4x(x^{2}+x)}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}+3x^{3}+3x^{2}+3x-x-4x^{3}+4x^{2}}{x(x^{2}+x)}

fog(x)=\frac{3x^{4}-x^{3}-x^{2}+2x}{x(x^{2}+x)}

This is the function fog(x).

The domain of a function is all the values the independent variable can assume.

For fog(x), denominator can be zero, so:

x(x^{2}+x) \neq 0

If x = 0, the function doesn't exist.

x^{2}+x \neq0

x(x+1) \neq0

x+1\neq0

x\neq-1

<u>Therefore, the domain of this function is: </u><u>-∞ < -1 or x > 0</u>

5 0
3 years ago
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