If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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7% of $5100 is 357
416.50 / 357 = 1.16
I will take 1.16 years to gain $416.50
Answer:
6x + y = 1
y = 1 - 6x
7x + 2(1 - 6x) = -3 substitute 1 - 6x in for y
7x + 2 - 12x = -3 combine like terms
2 - 5x = -3 subtract 2 from both sides
-5x = -5 divide by -5
x = 1
Answer:
try 21
Step-by-step explanation:
if not im as stuck as you are :(
