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Yakvenalex [24]
4 years ago
13

¡PLEASE HELP ME! I NEED to complete these Math exercises right now. Please help me guys...

Mathematics
1 answer:
max2010maxim [7]4 years ago
6 0

Answer:

which one?

Step-by-step explanation:

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F the experimental value for the percentage of o is 37%, the accepted value of the percentage of oxygen is 40%, what is the perc
fenix001 [56]
The percentage error can be calculated using the following rule:
% error = difference between values / accepted value

From the givens:
The accepted value = 40%
Difference between values = 40% - 37% = 3%

Substitute in the equation to get the percentage error as follows:
% error = (3/40) * 100 = 7.5%
3 0
3 years ago
Read 2 more answers
Given: f(x) = x - 7 and h(x) = 2x + 3<br><br> Write the rule for h(f(x)).
Andrei [34K]

Answer:

h(f(x)) = 2x - 11

Step-by-step explanation:

h(f(x)) is a "composite function."  We use the function f(x) as the input to the function h(x):

h(x) = 2x + 3, or 2( x ) + 3; replacing x with f(x), or x - 7, we get:

h(f(x)) = 2(x - 7) + 3, or

h(f(x)) = 2x - 14 + 3, or

h(f(x)) = 2x - 11

3 0
4 years ago
PLEASE HELP ME ON THIS ONE I REALLY DONT KNOW HOW TO DO THIS AND I JUST CAME TO AMERICA SO I DONT KNOW HOW TO DO THESE THINGS CO
eimsori [14]

a: Answer is cuboid

b: top & base will be 5*6 = 30 in ^2

both right & left side wil be 5*2 = 10 in^2

front & back will be 6*2 = 12 in^2

Hope that will help you :)

5 0
4 years ago
Solve the inequality
Pie

Answer:

- 0.6 \leqslant x  \leqslant 0.666 \: and \: x >   \sqrt[3]{7}

Step-by-step explanation:

The answer you are saying is correct if it was an equation

In inequalities the answer most of the times comes in ranges

The easiest way to find the range is by graphing the equation and finding the values of x for which the graph is above the x axis

There is a good graphing calculator app called desmos if u don't have one

5 0
3 years ago
20 POINTS!! ASAP, PLS SHOW WORK TYY
Sergeeva-Olga [200]

Answer:

\sin(\theta)=-\sqrt5/5\text{ and } \csc(\theta)=-\sqrt5\\\cos(\theta)=2\sqrt5/5\text{ and } \sec(\theta)=\sqrt5/2\\\tan(\theta)=-1/2\text{ and } \cot(\theta)=-2

Step-by-step explanation:

First, let's determine which quadrant our angle θ lies in.

Remember ASTC, where:

Everything is positive in QI,

Only sine (and cosecant) is positive in QII,

Only tangent (and cotangent) is positive in QIII,

And only cosine (and secant) is positive in QIV.

Since our tangent is negative, and our cosine is positive, this means that our θ <em>must</em> be in QIV.

In QIV, sine is negative, tangent is negative, and cosine is positive.

With that, let's figure out the remaining trig ratios.

We know that:

\tan(\theta)=-1/2

Remember that tangent is the ratio of the opposite side to the adjacent side.

Let's figure out our hypotenuse using the Pythagorean Theorem:

a^2+b^2=c^2

Substitute 1 for a and 2 for b (we can ignore the negative since we're squaring anyways). This yields:

(1)^2+(2)^2=c^2

Square:

1+4=c^2

Add:

c^2=5

Take the square root:

c=\sqrt{5}

So, our square root is √5.

So, our three sides are: Opposite=1, Adjacent=2, and Hypotenuse=√5.

Sine and Cosecant:

Remember that:

\sin(\theta)=opp/hyp

Substitute 1 for the opposite and √5 for the hypotenuse. This yields:

\sin(\theta)=1/\sqrt5

Rationalize:

\sin(\theta)=\sqrt5/5

And since our angle is in QIV, we add a negative:

\sin(\theta)=-\sqrt5/5

Cosecant is simply the reciprocal of sine. So:

\csc(\theta)=-\sqrt5

Cosine and Secant:

Remember that:

\cos(\theta)=adj/hyp

Substitute 2 for the adjacent and √5 for the hypotenuse. This yields:

\cos(\theta)=2/\sqrt5

Rationalize:

\cos(\theta)=2\sqrt5/5

Since our angle is in QIV, cosine stays positive.

Secant is the reciprocal of cosine. So:

\sec(\theta)=\sqrt5/2

Tangent and Cotangent:

We were given that:

\tan(\theta)=-1/2

To find cotangent, flip:

\cot(\theta)=-2

And we're done!

7 0
3 years ago
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