Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

Answer 1

Answer: y=-3x+29

Step-by-step explanation:

First put in y-intercept form to find the slope

$4x-12y=2\\-12y=-4x+2\\y=\frac{1}{3} x-\frac{1}{6}$

Slope of the 1st equation is 1/3-  the slope of the line perpendicular is the opposite reciprocal, so in the case it is -3

Use the point and the new slope to write the new equation in point slope format

$y-y_{1} =m(x-x_{1} )\\y-(-1)=-3(x-10)\\y+1=-3x+30\\y=-3x+29$