solution:
a) The mean value of gap w̅ is given by,
w̅= d̅ - a̅ - b̅ - c̅
w̅=06.520-0.150-2.000-3.000
w̅=0.020 in
bilateral tolerances of the gap is given by,
tw = ∑t
tw = 0.001+0.003+0.004+0.010= 0.018 in
w = 0.020 ± 0.018 in
b) if wmin =0.010 in , then
w̅ = wmin + tw
w̅ = 0.010+ 0.018=0.028 in
mean size of d is
d̅ = a̅ + b̅+ c̅+ w̅
d̅ =1.500+2.000+3.000+0.028
= 6.528 in
