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2 years ago

What is the area of this triangle?

Mathematics

1 answer:

Katen [24]2 years ago

3 0

18.81
Half (6.6) base times height (5.7)

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A sequence which terminates is called

vivado [14]

If a sequence terminates it is called a finite sequence

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2 years ago

How many sides does a cube have

Lostsunrise [7]

A cube has 6 sides on it. Just think of a dice.

Hope I Helped!!!

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3 years ago

Read 2 more answers

A function has x-intercept 3 and y-intercept 2. Which of the functions below could be this function?

Sergeeva-Olga [200]

we are given

x-intercept is 3

so,

a=3

y-intercept is 2

b=2

now, we can intercept formula of line

$\frac{x}{a} +\frac{y}{b}=1$

now, we can plug

a=3 and b=2

$\frac{x}{3} +\frac{y}{2}=1$

now, we will get rid of denominators

so, we can multiply both sides by 6

$6*\frac{x}{3} +6*\frac{y}{2}=6*1$

$2x +3y=6$

we can also write it as

$3y-6=-2x$

so, option-D..................Answer

3 0

3 years ago

Each year a car is worth 8% less than it was the year before. After 3 years, the car is worth $19,311.46. What was the original

vagabundo [1.1K]

Answer:

$24,800

Step-by-step explanation:

If a car is worth 8% less after one year, then it is worth 92% of the original value.

original value = x

after 1 year: 0.92x

after 2 years: 0.92(0.92x)

after 3 years: 0.92(0.92(0.92x))

0.92³x = $19,311.46

x = $19,311.46/0.92³

x = $24,800

3 0

2 years ago

You intend to estimate a population proportion with a confidence interval. The data suggests that the normal distribution is a r

SIZIF [17.4K]

Answer:

The critical value that corresponds to a confidence level of 99% is, 2.58.

Step-by-step explanation:

Consider a random variable X that follows a Binomial distribution with parameters, sample size n and probability of success p.

It is provided that the distribution of proportion of random variable X, $\hat p$ , can be approximated by the Normal distribution.

The mean of the distribution of proportion is, $\mu_{\hat p}=\hat p$

The standard deviation of the distribution of proportion is, $\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$ .

Then the confidence interval for the population proportion p is:

$CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n} }$

The confidence level is 99%.

The significance level is:

$\alpha =1-\frac{Confidence\ level}{100}=1-\frac{99}{100}=1-0.99=0.01$

Compute the critical value as follows:

$z_{\alpha /2}=z_{0.01/2}=z_{0.005}$

That is:

$P(Z>z)=0.005\\P(Z$

Use the z-table for the z-value.

For z = 2.58 the P (Z < z) = 0.995.

And for z = -2.58 the P (Z > z) = 0.005.

Thus, the critical value is, 2.58.

7 0

3 years ago