The equation of the ellipse in <em>standard</em> form is (x + 3)² / 100 + (y - 2)² / 64 = 1. (Correct choice: B)
<h3>What is the equation of the ellipse associated with the coordinates of the foci?</h3>
By <em>analytical</em> geometry we know that foci are along the <em>major</em> axis of ellipses and beside the statement we find that such axis is parallel to the x-axis of Cartesian plane. Then, the <em>standard</em> form of the equation of the ellipse is of the following form:
(x - h)² / a² + (y - k)² / b² = 1, where a > b (1)
Where:
- a - Length of the major semiaxis.
- b - Length of the minor semiaxis.
Now, we proceed to find the vertex and the lengths of the semiaxes:
a = 10 units.
b = 8 units.
Vertex
V(x, y) = 0.5 · F₁(x, y) + 0.5 · F₂(x, y)
V(x, y) = 0.5 · (3, 2) + 0.5 · (- 9, 2)
V(x, y) = (1.5, 1) + (- 4.5, 1)
V(x, y) = (- 3, 2)
The equation of the ellipse in <em>standard</em> form is (x + 3)² / 100 + (y - 2)² / 64 = 1. (Correct choice: B)
To learn more on ellipses: brainly.com/question/14281133
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If the vectors point towards the same direction, the magnitude of the vector quantities are added as in, C = A + B. If they point towards opposite direction, the magnitudes are subtracted giving a resultant vector equal to C = A - B.
Answer:
10 lbs
Step-by-step explanation:
7 qts x 5 qts = 35 qts broth
2 lbs x 5 lbs = 10 lbs barley
AB=48, DC=88
48+88=136
136÷2=68
Answer: LM=68
Remember that the length of the mid segment in a trapezoid is half the sum of the base lengths.
Answer:
Step-by-step explanation:
Simplifying
-3a + 8 = 2z + -12
Reorder the terms:
8 + -3a = 2z + -12
Reorder the terms:
8 + -3a = -12 + 2z
Solving
8 + -3a = -12 + 2z
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + -3a = -12 + -8 + 2z
Combine like terms: 8 + -8 = 0
0 + -3a = -12 + -8 + 2z
-3a = -12 + -8 + 2z
Combine like terms: -12 + -8 = -20
-3a = -20 + 2z
Divide each side by '-3'.
a = 6.666666667 + -0.6666666667z
Simplifying
a = 6.666666667 + -0.6666666667z
