675
15*45
3*5 5*9
3*3
3^3*5^2=675
Let W = width of package
Let H = height of package
Let L = length of package
The perimeter cab be one of the following:
P = 2(L + W), or
P = 2(L + H)
The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
2(L + 10) <= 108
L + 10 <= 54
L <= 44 in
When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in
To satisfy both of these conditions requires that L <= 39 in.
Answer: 39 inches
Let's assume
number of child tickets sold on saturday is x
number of adult tickets sold on saturday is y
On saturday, twice as many adult tickets as child tickets were sold
so, we get

child admission is $6.30 and adult admission is $9.60
a total sales of $535.50
we get

now, we can plug y=2x

now, we can solve for x


now, we can find y


so,
number of child tickets sold on saturday is 21
number of adult tickets sold on saturday is 42.........Answer
Answer:
all of these are congents
Step-by-step explanation:
Each coner
Answer:
27/10, or 2 7/10 kg
Step-by-step explanation:
We first have the expression 15/100*18, which simplifies to 3/20*18. If we multiply and simplify, we get 27/10, or 2 7/10