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3 years ago

PLEASE ANSWER THIS

Mathematics

1 answer:

saveliy_v [14]3 years ago

4 0

B) If the line is parallel, that means the slope is the same.
The slope for the original line is $\frac{-1-0}{6-2}$ = $\frac{-1}{4}$ .
The second form of coral line would be y = -1/4x + (any number). You could use y = -1/4x + 3.

c) Solve 12x = 24 + 3y for y.
3y = 12x - 24
y = 4x - 8
Perpendicular lines have negative reciprocal slopes... the negative reciprocal for -1/4 is 4. So yes, the third coral structure is perpendicular to the first coral.

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In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.

bezimeni [28]

Given:

In the circle, $m(\overarc{VUX})=152^\circ$ and $m(\angle MUV)=77^\circ$ .

To find:

The following measures:

(a) $m\angle VUX$

(b) $m\angle UXW$

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

$m(VUX)=2\times m\angle VWX$

$152^\circ=2\times m\angle VWX$

$\dfrac{152^\circ}{2}=m\angle VWX$

$76^\circ=m\angle VWX$

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

$m\angle VUX+m\angle VWX=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle VUX+76^\circ=180^\circ$

$m\angle VUX=180^\circ-76^\circ$

$m\angle VUX=104^\circ$

Now,

$m\angle UXW+m\angle UVW=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle UXW+77^\circ =180^\circ$

$m\angle UXW=180^\circ-77^\circ$

$m\angle UXW=103^\circ$

Therefore, $m\angle VUX=104^\circ$ and $m\angle UXW=103^\circ$ .

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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