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miskamm [114]
3 years ago
14

What is it's speed at this time? A rocket blasts off and moves straight upward from the launch pad with constant acceleration. A

fter 2.7s the rocket is at a height of 86m
Physics
1 answer:
zhenek [66]3 years ago
6 0

Answer: 31.85 m/s

Explanation:

Since we are talking about constant acceleration, we can use the following equation to find the speed s of the rocket:

s=\frac{d}{t}

Where:

d=86 m is the distance the rocket has traveled

t=2.7 s is the time in which the rocket has traveled the distance d

Solving the equation with the given data:

s=\frac{86 m}{2.7 s}

s=31.85 m/s This is the rocket's speed

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4 years ago
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Two massless bags contain identical bricks, each brick having a mass M. Initially, each bag contains four bricks, and the bags m
stepladder [879]

Answer: F_{2}=\frac{3}{4}F_{1}

Explanation:

According to Newton's law of universal gravitation:

F=G\frac{m_{1}m_{2}}{r^2}

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant.

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

In this case we have two situations:

1) Two bags with masses 4M and 4M mutually exerting a gravitational attraction F_{1} on each other:

F_{1}=G\frac{(4M)(4M)}{r^2}   (1)

F_{1}=G\frac{16M^2}{r^2}   (2)

F_{1}=16\frac{GM^2}{r^2}   (3)

2) Two bags with masses 2M and 6M mutually exerting a gravitational attraction F_{2} on each other (assuming the distance between both bags is the same as situation 1):

F_{2}=G\frac{(2M)(6M)}{r^2}   (4)

F_{2}=G\frac{12M^2}{r^2}   (5)

F_{2}=12\frac{GM^2}{r^2}   (6)

Now, if we isolate \frac{GM^2}{r^2} from (3):

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Substituting \frac{GM^2}{r^2}  found in (7) in (6):

F_{2}=12(\frac{F_{1}}{16})   (8)

F_{2}=\frac{12}{16}F_{1}   (9)

Simplifying, we finally get the expression for F_{2}  in terms of F_{1} :

F_{2}=\frac{3}{4}F_{1}  

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4 years ago
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Serhud [2]

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4 0
3 years ago
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Answer:

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