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yanalaym [24]
3 years ago
9

How can you change the size, shape, location of a shadow?

Physics
2 answers:
tigry1 [53]3 years ago
6 0
Its all in how straight you stand
Mumz [18]3 years ago
5 0
You can do this by moving my the location of the light source without doing anything to the actual object
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Why is the law of gravity an example of a universal law? a Gravity is the attraction of any mass to any other mass. b Gravity is
konstantin123 [22]
D and A are quite the same, but I think D is more general.
3 0
3 years ago
Pls help!! i don’t understand what i am supposed to do.
liq [111]

Well, my German isn't as sharp as it used to be, but it looks like you're supposed to use the symbols at the top and draw two circuits ... one where the switch is closed and the light is shining, the other where the switch is open and the light is out.

That should be pretty easy for you. Just hook up one battery, one switch, and one light, all in series. Then opening and closing the switch makes the light go on and off.

7 0
3 years ago
Geothermal energy generation uses what kind of turbine?
aliya0001 [1]

Answer:

electromagnetic induction

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6 0
3 years ago
Why does conduction occur mainly in the lower atmosphere
Rus_ich [418]
Heat energy is transferred through Earth's atmosphere<span> in three ways: radiation,</span>conduction<span>, and convection. hoped this helped</span>
4 0
3 years ago
In a simple model of the hydrogen atom, the electron moves in a circular orbit of radius 0.053nm around a stationary proton. par
Alenkasestr [34]
<span>Here the force that is applied between the electron and proton is centripetal, so equate the two forces to determine the velocity.
 We know charge of the electron which for both Q1 and Q2, e = 1.60 x 10^-19 C
 The Coulombs Constant k = 9.0 x 10^9
 Radius r = 0.053 x 10^-9m = 5.3 x 10^-11 m
  Mass of the Electron = 9.11 x 10^-31
  F = k x Q1 x Q2 / r^2 = m x v^2 / r(centripetal force)
  ke^2 / r^2 = m x v^2 / r => v^2 = ke^2 / m x r
 v^2 = ((1.60 x 10^-19)^2 x 9.0 x 10^9) / (9.11 x 10^-31 x 5.3 x 10^-11 )
 v^2 = 4.77 x 10^12 = 2.18 x 10^6 m/s
 Since one orbit is the distance,
  one orbit = circumference = 2 x pi x r; distance s = v x t.
 v x t = 2 x pi x r => t = (2 x 3.14 x 5.3 x 10^-11) / (2.18 x 10^6)
  t = 33.3 x 10^-11 / 2.18 x 10^6 = 15.27 x 10^-17 s
 Revolutions per sec = 1 / t = 1 / 15.27 x 10^-17 = 6.54 x 10^15 Hz</span>
6 0
3 years ago
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