Complete Question:
In the same configuration of the previous problem 3, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a = 13.5 cm. Each wire carries 7.50 A, and the currents are out of the page in wires 1 and 4 and into the page in wires 2 and 3.
a) Draw a diagram in a (x,y) plane of the four wires with wire 4 perpendicular to the origin. Indicate the current's directions.
b) Draw a diagram of all magnetic fields produced at the position of wire 3 by the other three currents.
c) Draw a diagram of all magnetic forces produced at the position of wire 3 by the other three currents.
d) What are magnitude and direction of the net magnetic force per meter of wire length on wire 3?
Answer:
force, 1.318 ₓ 10⁻⁴
direction, 18.435°
Explanation:
The attached file gives a breakdown step by step solution to the questions
Answer:
D. none of them.
Explanation:
This is because Ohm's law is:
Voltage = Current × Resistance
or,
V = IR
Becuse your weighting with chalk that has pigment
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Answer:
The value of the average convection coefficient is 20 W/Km².
Explanation:
Given that,
For first object,
Characteristic length = 0.5 m
Surface temperature = 400 K
Atmospheric temperature = 300 K
Velocity = 25 m/s
Air velocity = 5 m/s
Characteristic length of second object = 2.5 m
We have same shape and density of both objects so the reynold number will be same,
We need to calculate the value of the average convection coefficient
Using formula of reynold number for both objects
![R_{1}=R_{2}](https://tex.z-dn.net/?f=R_%7B1%7D%3DR_%7B2%7D)
![\dfrac{u_{1}L_{1}}{\eta_{1}}=\dfrac{u_{2}L_{2}}{\eta_{2}}](https://tex.z-dn.net/?f=%5Cdfrac%7Bu_%7B1%7DL_%7B1%7D%7D%7B%5Ceta_%7B1%7D%7D%3D%5Cdfrac%7Bu_%7B2%7DL_%7B2%7D%7D%7B%5Ceta_%7B2%7D%7D)
![\dfrac{h_{1}L_{1}}{k_{1}}=\dfrac{h_{2}L_{2}}{k_{2}}](https://tex.z-dn.net/?f=%5Cdfrac%7Bh_%7B1%7DL_%7B1%7D%7D%7Bk_%7B1%7D%7D%3D%5Cdfrac%7Bh_%7B2%7DL_%7B2%7D%7D%7Bk_%7B2%7D%7D)
Here, ![k_{1}=k_{2}](https://tex.z-dn.net/?f=k_%7B1%7D%3Dk_%7B2%7D)
![h_{2}=h_{1}\times\dfrac{L_{1}}{L_{2}}](https://tex.z-dn.net/?f=h_%7B2%7D%3Dh_%7B1%7D%5Ctimes%5Cdfrac%7BL_%7B1%7D%7D%7BL_%7B2%7D%7D)
![h_{2}=\dfrac{q}{T_{2}-T_{1}}\times\dfrac{L_{1}}{L_{2}}](https://tex.z-dn.net/?f=h_%7B2%7D%3D%5Cdfrac%7Bq%7D%7BT_%7B2%7D-T_%7B1%7D%7D%5Ctimes%5Cdfrac%7BL_%7B1%7D%7D%7BL_%7B2%7D%7D)
Put the value into the formula
![h_{2}=\dfrac{10000}{400-300}\times\dfrac{0.5}{2.5}](https://tex.z-dn.net/?f=h_%7B2%7D%3D%5Cdfrac%7B10000%7D%7B400-300%7D%5Ctimes%5Cdfrac%7B0.5%7D%7B2.5%7D)
![h_{2}=20\ W/Km^2](https://tex.z-dn.net/?f=h_%7B2%7D%3D20%5C%20W%2FKm%5E2)
Hence, The value of the average convection coefficient is 20 W/Km².