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3 years ago

Multiply each of the hourly rate by time and a half to calculate the overtime rate

Mathematics

2 answers:

aleksandrvk [35]3 years ago

5 0

There are no times to calculate but my best guess is B hope this helps!:D

AveGali [126]3 years ago

3 0

The answer is C,because it half a number

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Find the value of x the missing leg

Fantom [35]

Answer:

the answer is 17

wlecome

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The mean height of 10 girls is 154cm. The mean height of 8 boys is 162cm. What is the mean height of the class?

olganol [36]

Answer:

158cm

Step-by-step explanation:

154+162=316

316/2=158

8 0

2 years ago

How would I do the steps to solve this?

allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

$R(p) = -10p^2+800p$

Taking derivative wrt p

$\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\$

Now putting R'(p) = 0

$-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40$

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

$R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000$

The maximum revenue is 16000 dollars (at p = 40)

3 0

2 years ago

Geometry area question. Please help!

timurjin [86]

You can calculate polygon area with only apothem OR side length.

apothem only
area = apothem^2 * 6 * tan (180/6)
area = 10.4^2 * 6 * 0.57735
area = 108.16 * 3.4641 
area = 374.677056 square yards

side length only
area = 6 * 12^2 * / 4*tan(30)
area = 864 / 4 * 0.57735
area = 864 / 2.3094 
area = 374.1231488698 square yards

If apothem and side length were given with more precision, the answers would be closer.

Source:
http://www.1728.org/polygon.htm

5 0

2 years ago

2. En la ciudad de Quito, en la temporada fría, se registran temperaturas que van desde los 5 °C hasta los 18 °C. En la temporad

natulia [17]

Answer:

(See explanation below for further detail/Véase la explicación abajo para mayores detalles)

Step-by-step explanation:

(This exercise is written in Spanish and explanations will be held in such language)

a) Las temperaturas quedan representadas a continuación:

Quito - Temporada Fría

Intervalo

$5 ^{\circ}C \leq t \leq 18^{\circ}C$ (Este intervalo indica si el dato puede pertenecer a la temporada fría)

Conjunto

$C = \{\forall t \in \mathbb {R}| 5 \leq t \leq 18\}$ (Este conjunto acumula todo el registro de las temperaturas de la temporada fría)

Quito - Temporada Cálida

Intervalo

$4 ^{\circ}C \leq t \leq 30^{\circ}C$ (Este intervalo indica si el dato puede pertenecer a la temporada cálida)

Conjunto

$H = \{\forall t \in \mathbb {R}| 4 \leq t \leq 30\}$ (Este conjunto acumula todo el registro de las temperaturas de la temporada cálida)

b) La temperatura de la ciudad de Quito pertenece esencialmente a dos intervalos:

Intervalo de Temporada Fría:

$5 ^{\circ}C \leq t \leq 18^{\circ}C$

Intervalo de Temporada Cálida:

$4 ^{\circ}C \leq t \leq 30^{\circ}C$

c) Toda temperatura mayor o igual que 4 °C y menor o igual que 30 °C.

d) Temperaturas mayores o iguales a 5 °C y menores o iguales a 18 °C.

e) Temperaturas mayores o iguales a 4 °C y menores o iguales a 30 °C.

6 0

3 years ago