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Elden [556K]
3 years ago
8

Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly. Without looking, Allen draws one letter. Expressed as a fra

ction, decimal, and percentage, what is the probability that Allen will NOT select a consonant?
Mathematics
2 answers:
lawyer [7]3 years ago
7 0
Im pritty sure it would be 30%

Ad libitum [116K]3 years ago
3 0

Answer: \text{P(Not consonant)}=\frac{3}{8}

In decimal, 0.375

In percentage,37.5\%

Step-by-step explanation:

Given: Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly.

Total number of letters= 8

The number of consonant=5 (S, L, C, T, D )

The number of letters which are not consonants (vowels)=8-5=3

Now, the probability that Allen will NOT select a consonant is given by :-

\text{P(Not consonant)}=\frac{\text{number of non consonant letters}}{\text{total letters}}

\\\Rightarrow\ \text{P(Not consonant)}=\frac{3}{8}

In decimal, \frac{3}{8}=0.375

In percentage,\frac{3}{8}\times100=37.5\%

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<em>Comment on the second question</em>

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