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3 years ago

8(5021)(3054)+(-8)(-5021)(-3054)+3

Mathematics

2 answers:

kifflom [539]3 years ago

5 0

Answer:

Step-by-step explanation:

first two terms cancel eachother out!

mina [271]3 years ago

3 0

Answer:

Step-by-step explanation:

8(5021)(3054) + (-8)(-5021)(-3054) + 3 = 8(5021)(3054) - (8)(5021)(3054)+3

= 0 + 3

= 3

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Please help!!!!!!! I only have 20 minutes left!!

slavikrds [6]

Step-by-step explanation:

You need to find the total number of students the pie chart will represent:

17 + 35 + 38 = 90

So you know, 360° represents 90 people

You can then find out the angle for each person: 360 ÷ 90 = 4

Each person is 4°

1. 17 people took French so you would do 4° × 17 = 68°

2. 35 people took German so you would do 4° × 35 = 140°

3. 38 people took Italian so you would do 4° × 38 = 152°

17 out of 90 people chose french so the probability would be 17/90

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2 years ago

What are the zeros of the function f(x) =x^2-11x+24 ?

UNO [17]

Answer:

there is none

Step-by-step explanation:

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3 years ago

hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and

Mariulka [41]

Given:

The equation is,

$2\log _3x-\log _3(x-2)=2$

Explanation:

Simplify the equation by using logarthimic property.

$\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{ \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}$

Simplify further.

$\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}$

Solve the quadratic equation for x.

$\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}$

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

$\begin{gathered} x-6=0 \\ x=6 \end{gathered}$

For (x - 3) = 0,

$\begin{gathered} x-3=0 \\ x=3 \end{gathered}$

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

$\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}$

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

$\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}$

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0

1 year ago

James defines an angle as "a figure consisting of two rays." His statement is not precise enough because he should specify that

riadik2000 [5.3K]

James should define that the rays must be collinear. the two rays coming from the same point will form collinear rays which will form an angle at end point.

The statement of james should be precise in order to clearly explain the angle formation.

The two non collinear rays will form an angle at end point where they meet with each other.

The defined vertex will form the appropriate angle. there should be defined term for the non collinear rays.

Learn more at brainly.com/question/24373158

3 0

2 years ago

Read 2 more answers

Find the slope of the line going through the points (0, -5) and (-2,1)

kvasek [131]

Answer:

$\displaystyle m=-3$