Answer:
Yes, overloading is one of the methods which are popular in programming language. Overloading basically refers to the same function but different signature called function overloading or method overloading. It is the ability to define the multiples method by using the single identifier.
The overloading is important because it has the ability to design the multiple method by using similar name. It also provide the high flexibility to the programmers to call the same method in the data. overloading basically provide the high clarity in the code.
Overloading is used to achieved the compile time polymorphism.
Following are program of function overloading in c++ are:
Class abc // creating class
{
public:
int p;
void fun() // function fun with no parameter/
{
cout<<” hello “;
}
void fun(int a) // function fun with parameter
{
p=a;
cout<<p;
}
};
int main() // main function
{
abc ob; // creating object
ob.fun();// print hello;
ob.fun(6);// print 6
return 0;
}
Explanation:
In this program the function fun() have same name but different signature in the main method we create the object of class abc i.e ob. ob.fun() this statement called the function with no parameter and ob.fun(6) this statement will called the function with integer parameter.
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Answer:
True.
The code skips the else command
Explanation:
I will answer this question with the following code segment
<em>n = 1</em>
<em>If n > 0:</em>
<em> Print("greater than 0")</em>
<em>else:</em>
<em> Print("not greater than 0")</em>
<em />
From the code segment above
<em>Print("greater than 0")</em> will be executed because the condition <em>If n > 0 </em>is true
Since the if condition is true, the else condition will not be executed
Answer:
false
Explanation:
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