Answer:
Step-by-step explanation:
Given:
Type of Flowers = 5
To choose = 4
Required
Number of ways 4 can be chosen
The first flower can be chosen in 5 ways
The second flower can be chosen in 4 ways
The third flower can be chosen in 3 ways
The fourth flower can be chosen in 2 ways
Total Number of Selection = 5 * 4 * 3 * 2
Total Number of Selection = 120 ways;
Alternatively, this can be solved using concept of Permutation;
Given that 4 flowers to be chosen from 5,
then n = 5 and r = 4
Such that
![nPr = \frac{n!}{(n - r)!}](https://tex.z-dn.net/?f=nPr%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n%20-%20r%29%21%7D)
Substitute 5 for n and 4 for r
![5P4 = \frac{5!}{(5 - 4)!}](https://tex.z-dn.net/?f=5P4%20%3D%20%5Cfrac%7B5%21%7D%7B%285%20-%204%29%21%7D)
![5P4 = \frac{5!}{1!}](https://tex.z-dn.net/?f=5P4%20%3D%20%5Cfrac%7B5%21%7D%7B1%21%7D)
![5P4 = \frac{5*4*3*2*1}{1}](https://tex.z-dn.net/?f=5P4%20%3D%20%5Cfrac%7B5%2A4%2A3%2A2%2A1%7D%7B1%7D)
![5P4 = \frac{120}{1}](https://tex.z-dn.net/?f=5P4%20%3D%20%5Cfrac%7B120%7D%7B1%7D)
![5P4 = 120](https://tex.z-dn.net/?f=5P4%20%3D%20120)
Hence, the number of ways the florist can chose 4 flowers from 5 is 120 ways
What’s the rest of the question
Yes it does equal since they are equivalent!
Answer:
Step-by-step explanation:
given are four statements and we have to find whether true or false.
.1 If two matrices are equivalent, then one can be transformed into the other with a sequence of elementary row operations.
True
2.Different sequences of row operations can lead to different echelon forms for the same matrix.
True in whatever way we do the reduced form would be equivalent matrices
3.Different sequences of row operations can lead to different reduced echelon forms for the same matrix.
False the resulting matrices would be equivalent.
4.If a linear system has four equations and seven variables, then it must have infinitely many solutions.
True, because variables are more than equations. So parametric solutions infinite only is possible
Answer:
Y=-2/3x+6
Step-by-step explanation:
Y=-2/3x+b
2=-2/3•6+b
2=-4+b
6=b