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Genrish500 [490]

3 years ago

15

From least to greatest verify your answer by graphing the numbers on a number line?

1 answer:

mafiozo [28]3 years ago

7 0

Put 0 in the middle and put the #s around it.

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Please help me I will give brainiest.

Natali [406]

1. A

2. B

3. A

4. C

5. B and C

7 0

3 years ago

Read 2 more answers

Write an equation that is parallel to the line y = -5x + 2 and passes through the point (0, 3).

nikklg [1K]

---------------------------------------
Slope :
---------------------------------------
y = -5x + 2
Slope = -5

---------------------------------------
y - intercept :
---------------------------------------
At (0. 3), y-intercept = 3

---------------------------------------
Equation :
---------------------------------------
y = mx + b
y = -5x + 3

---------------------------------------
Answer : y = -5 + 3
---------------------------------------

7 0

3 years ago

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

4 0

3 years ago

PLEASE ANSWER ASAP!! WILL GIVE 50 POINTS! AND BRAINLIST!

levacccp [35]

$\frac{3}{5} - \frac{1}{4} = \frac{7}{20}$
then
$\frac{7}{20} \div \frac{7}{10} = \frac{1}{2}$

4 0

3 years ago

What is the completely factored form of f(x) = 6x3 – 13x2 – 4x + 15?

lana66690 [7]

Answer:

= -4x + 7 is the correct answer

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers